Ask question

Ask question

All categories

2 years ago

12

Bart bought a digital camera with a list price of $219 from an online store offering a 6 percent discount. He needs to pay $7.50

for shipping. What was Bart's total cost?

2 answers:

nikitadnepr [17]2 years ago

4 0

So the problem ask to calculate the total cost of the camera which has a list price of $219 and has a 6% discount in the online shop. So base on that data, and in y further solution, the answer would be $213.36. I hope you are satisfied with my answer and feel free to ask for more

Marina86 [1]2 years ago

4 0

Bart bought a digital camera with a list price of $219 from an online store offering a 6 percent discount.

Price of digital camera = $219, 6% discount= $\frac{6}{100} =0.06$

Discount amount= Price * discount percentage

= 219 * 0.06 = 13.14

Price of camera after discount = Price - discount amount = 219 - 13.14 = 205.86

He needs to pay $7.50 for shipping

Bart's total cost = 205.86 + 7.50 = $213.36

You might be interested in

Carlie runs two different business. She needs to pay $100 for materials, and pay her associates $12 per hour for

Marrrta [24]

Answer:

$375+12ct_c+10lt_l$

Step-by-step explanation:

Carlie is running two different business.

She needs to pay:

- For the childcare business,

100$ for the materials

12$ per hour for each associate for her childcare business, so if we call:

$t_c$ = the number of hours worked by each associate

$c$ = the number of associates

The total cost for the childcare business is:

$C=100+12ct_c$ (1)

- For the lawn care business,

275$ for the materials

10$ per hour for each associate for her lawn care business, so if we call:

$t_l$ = the number of hours worked by each associate

$l$ = the number of associates

The total cost for the lawn care business is:

$L=275+10lt_l$ (2)

Therefore, the total expenses from both businesses is the sum of (1) and (2):

$T=C+L=100+12ct_c+275+10lt_l = 375+12ct_c+10lt_l$

3 0

2 years ago

What is the area of △FGH to the nearest tenth of a square meter? The image is of a triangle GHF with base GH length 2m, FG is 2.

Gnesinka [82]

First, we are going to use the law of cosines to find the length of the line segment FH:
$FH= \sqrt{2.5^{2}+2^{2}-(2)(2.5)Cos(121)}$
$FH= \sqrt{2.5^{2}+2^{2}-5Cos(121)}$
$FH=3.2$

Next, we are going to use the semi-perimeter formula: $s= \frac{GH+FG+FH}{2}$
$s= \frac{2+2.5+3.2}{2}$
$s= \frac{7.7}{2}$
$s=3.9$

Now that we have the semi-perimeter of our triangle, we can find its area using Heron's formula:
$A= \sqrt{s(s-GH)(s-FG)(s-FH)}$
$A= \sqrt{3.9(3.9-2)(3.9-2.5)(3.9-3.2)}$
$A= \sqrt{3.9(1.9)(1.4)(0.7)}$
$A=2.7m^{2}$

We can conclude that the area of the triangle <span>GHF is 2.7 </span> $m^{2}$ .

3 0

2 years ago

Luis made 80% of what he made last week.If he made 72$ this week,how much did he make last week

IceJOKER [234]

Let

x--------> the amount in dollars that Luis make last week

we know that

$80\% =\frac{80}{100}=0.80$

$0.80x=72\$$ ------> equation that represent the situation

solve for x

Divide by $0.80$ both sides

$0.80x/0.80=72\$/0.80$

$x=72\$/0.80$

$x=90\$$

therefore

<u>the answer is</u>

$90\$$

4 0

2 years ago

Read 2 more answers

Determine the values of c so that the following functions represent joint probability distributions of the random variables X an

Anna11 [10]

Answer:

The joint probility density will be c = 1/36

The joint probability distribution will be c = 1/15

Step-by-step explanation:

For step by step explanation see the pucture attached

7 0

2 years ago

Read 2 more answers

Karina solves the system using linear combination and arrives at the equation 116y = 96.28. She then solves this equation for y.

igomit [66]

116y =96.28
116y = 96.28
---- ---------
116 116

y = .83

5 0

2 years ago