The <em><u>correct answer</u></em> is:
Ken will have run 3 laps and Hamid will have run 4.
Explanation:
To find this, we first find the number of seconds that will have passed when they meet again. We use the LCM, or least common multiple, for this. First we find the prime factorization of each number:
80 = 10(8)
10 = 5(2)
8 = 2(4)
4 = 2(2)
80 = 2(2)(2)(5)(2)
60 = 10(6)
10 = 5(2)
6 = 2(3)
60 = 2(2)(3)(5)
For the LCM, we multiply the common factors by the uncommon. Between the two numbers, the common factors are 2, 2 and 5. This makes the uncommon 2, 2, and 3, and makes our LCM
2(2)(5)(2)(2)(3) = 240
This means every 240 seconds they will both be at the start line.
Since Ken completes a lap in 80 seconds, he completes 240/80 = 3 laps in 240 seconds.
Since Hamid completes a lap in 60 seconds, he completes 240/60 = 4 laps in 240 seconds.
Well there similar because your adding 10 more or 10× since from ones to the tens is 10×
Answer:
Step-by-step explanation:
Given that X is a normal random variable with parameters µ = 10 and σ 2 = 36,
X is N(10, 6)
Or z = 
is N(0,1)
a) P(X > 5),
=
(b) P(4 < X < 16),
=
(c) P(X < 8),
=
(d) P(X < 20),
=
(e) P(X > 16).
=P(Z>-0.6667)
= 0.2524
Width of the actual barrier = 1.2 miles
Width of the barrier in the blueprint = 2 inches
2 inch dimension of blueprint = 1.2 miles of original
So, 1 inch dimension of blueprint = 1.2/2 = 0.6 miles.
Since the length of the barrier in the blueprint = 9 inches,
length of the actual barrier = 9(0.6) = 5.4 miles.
The answer is class intervals. A big set of data are grouped into different classes to get a hint of the distribution, and the range of such class of data is known as the Class Interval. In other words, these are range of scores in a group frequency distribution. Class intervals are commonly equal in width and are mutually exclusive. The middle of an interval is called a class mark and the ends of a class interval are called class limits. To calculate the class interval, divide the range by the number of classes.
