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bixtya [17]
2 years ago
5

If X is a normal random variable with parameters µ = 10 and σ 2 = 36, compute

Mathematics
1 answer:
alex41 [277]2 years ago
6 0

Answer:

Step-by-step explanation:

Given that X is a normal random variable with parameters µ = 10 and σ 2 = 36,

X is N(10, 6)

Or z = \frac{x-10}{6}

is N(0,1)

a)  P(X > 5),

=P(Z>-0.8333)\\=0.7977

(b) P(4 < X < 16),

=P(|z|

(c) P(X < 8),

=P(Z

(d) P(X < 20),

=P(Z

(e) P(X > 16).

=P(Z>-0.6667)

= 0.2524

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Math 9:The floor of conference hall can be covered completely with tiles. Its length is 36 ft longer than its width. The area of
valentina_108 [34]
What is the question?
I'm assuming it is to find the length and width.
+_= plus or minus
(X+36)
____________
| |
(X) | |
|____________|

X^2+36X-2040<0
X<-36+_(36^2-4*-2040)^(1/2)
-----------------------------------
2
X<-18+_2((591)^(1/2))
This is probably not what you wanted, sorry
8 0
2 years ago
Is AB parallel to Bo? Explain.
Svetradugi [14.3K]

Answer:

AB parallel to CD because both lines have a slope of

of 4/3

Step-by-step explanation:

The question is not complete, there is no graph.

A graph for the question is attached below.

From the image attached below, line 1 passes through points A = (-3, -3) and point B = (0, 1) while line 2 passes through point C = (0, -5) and point D = (3, -1).

Two parallel are said to be parallel if the have the same slope. The slope of a line passing through points:

(x_1,y_1)\ asnd\ (x_2,y_2).\ The\ slope \ is\ given\ as:\\\\Slope(m)=\frac{y_2-y_1}{x_2-x_1}

Line 1 passes through points A = (-3, -3) and point B = (0, 1), the slope of line 1 is:

Slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{1-(-3)}{0-(-3)}=\frac{1+3}{0+3}=\frac{4}{3}

Line 2 passes through point C = (0, -5) and point D = (3, -1). the slope of line 2 is:

Slope(m)=\frac{y_2-y_1}{x_2-x_1}=\frac{-1-(-5)}{3-0}=\frac{-1+5}{3}=\frac{4}{3}

Therefore AB parallel to CD because both lines have a slope of

of 4/3

7 0
2 years ago
Andre and Diego were each trying to solve 2x+6=3x−8. Describe the first step they each make to the equation. The result of Andre
Oksi-84 [34.3K]

Answer:

  • Andre subtracted 3x from both sides
  • Diego subtracted 2x from both sides

Step-by-step explanation:

<u>Andre</u>

Comparing the result of Andre's work with the original, we see that the "3x" term on the right is missing, and the x-term on the left is 3x less than it was. It is clear that Andre subtracted 3x from both sides of the equation.

__

<u>Diego</u>

Comparing the result of Diego's work with the original, we see that the "2x" term on the left is missing, and the x-term on the right is 2x less than it was. It is clear that Diego subtracted 2x from both sides of the equation.

_____

<em>Comment on their work</em>

IMO, Diego has the right idea, as his result leaves the x-term with a positive coefficient. He can add 8 and he's finished, having found that x=14.

Andre can subtract 6 to isolate the variable term, and that will give him -x=-14. This requires another step to get to x=14. Sometimes minus signs get lost, so this would not be my preferred sequence of steps.

As a rule, I like to add the opposite of the variable term with the least (most negative) coefficient. This results in the variable having a positive coefficient, making errors easier to avoid.

3 0
1 year ago
PLEASE HELP ME!
algol13

Step-by-step explanation:

1.\sum_{i=1}^{5}3i

The simplest method is "brute force".  Calculate each term and add them up.

∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)

∑ = 3 + 6 + 9 + 12 + 15

∑ = 45

2.\sum_{k=1}^{4}(2k)^{2}

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²

∑ = 4 + 16 + 36 + 64

∑ = 120

3.\sum_{k=3}^{6}(2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)

∑ = -4 + -2 + 0 + 2

∑ = -4

4. 1 + 1/4 + 1/16 + 1/64 + 1/256

This is a geometric sequence where the first term is 1 and the common ratio is 1/4.  The nth term is:

a = 1 (1/4)ⁿ⁻¹

So the series is:

\sum_{j=1}^{7}(\frac{1}{4})^{j-1}

5. -5 + -1 + 3 + 7 + 11

This is an arithmetic sequence where the first term is -5 and the common difference is 4.  The nth term is:

a = -5 + 4(n−1)

a = -5 + 4n − 4

a = 4n − 9

So the series is:

\sum_{j=1}^{5}(4j-9)

5 0
2 years ago
Every day, Jorge buys a lottery ticket. Each ticket has a probability of of winning a prize. After six days, what is the probabi
Romashka [77]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Every day, Jorge buys a lottery ticket. Each ticket has a 0.16 probability of winning a prize. After six days, what is the probability that Jorge has won at least one prize? Round your answer to four decimal places.

Answer:

The probability that Jorge has won at least one prize after six days is

P(at least 1 win) = 0.6487

Step-by-step explanation:

Every day, Jorge buys a lottery ticket which has a 0.16 chance of winning a prize.

We want to find out the probability that Jorge has won at least one prize after six days.

P(at least 1 win) = 1 - P(not winning for 6 days)

We know that the probability of winning is 0.16 then the probability of not winning is

P(not winning) = 1 - 0.16 = 0.84

For 6 days,

P(not winning for 6 days) = 0.84×0.84×0.84×0.84×0.84×0.84

P(not winning for 6 days) = 0.84⁶

P(not winning for 6 days) = 0.3513

Finally,

P(at least 1 win) = 1 - P(not winning for 6 days)

P(at least 1 win) = 1 - 0.3513

P(at least 1 win) = 0.6487

6 0
2 years ago
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