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vazorg [7]
2 years ago
11

5(0.04y-0.08) >3(0.2y-0.05-0.4y)

Mathematics
1 answer:
MAXImum [283]2 years ago
3 0

0.08(y + -1) + 0.12y = 0.14 + -0.05(10)

Reorder the terms:

0.08(-1 + y) + 0.12y = 0.14 + -0.05(10)

(-1 * 0.08 + y * 0.08) + 0.12y = 0.14 + -0.05(10)

(-0.08 + 0.08y) + 0.12y = 0.14 + -0.05(10)

Combine like terms: 0.08y + 0.12y = 0.2y

-0.08 + 0.2y = 0.14 + -0.05(10)

Multiply -0.05 * 10

-0.08 + 0.2y = 0.14 + -0.5

Combine like terms: 0.14 + -0.5 = -0.36

-0.08 + 0.2y = -0.36

Solving

-0.08 + 0.2y = -0.36

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '0.08' to each side of the equation.

-0.08 + 0.08 + 0.2y = -0.36 + 0.08

Combine like terms: -0.08 + 0.08 = 0.00

0.00 + 0.2y = -0.36 + 0.08

0.2y = -0.36 + 0.08

Combine like terms: -0.36 + 0.08 = -0.28

0.2y = -0.28

Divide each side by '0.2'.

y = -1.4

Simplifying

y = -1.4

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Step-by-step explanation:

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Read 2 more answers
If r is the midpoint of qs rs=2x-4, st= 4x-1 and rt = 8x-43 find qs
sammy [17]

Answer:

QS=68\ units

Step-by-step explanation:

step 1

Find the value of x

we know that

r is the midpoint of qs

so

QR=RS

QS=QR+RS------> QS=2RS -----> equation A

RT=RS+ST ----> equation B

see the attached figure to better understand the problem

Substitute the given values in the equation B and solve for x

8x-43=(2x-4)+(4x-1)

8x-43=6x-5

8x-6x=43-5

2x=38

x=19

step 2

Find the value of RS

RS=2x-4

substitute the value of x

RS=2(19)-4

RS=34\ units

step 3

Find the value of QS

Remember equation A

QS=2RS

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6 0
1 year ago
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