Answer: E(Y) = 1.6 and Var(Y)=1.12
Step-by-step explanation:
Since we have given that
X 0 1 2
P(X) 0.4 0.4 0.2
Here, number of games = 2
So, 
Since 
are independent variables.
so, ![E[Y]=2E[X]\\\\Var[Y]=2Var[X]](https://tex.z-dn.net/?f=E%5BY%5D%3D2E%5BX%5D%5C%5C%5C%5CVar%5BY%5D%3D2Var%5BX%5D)
So, we get that
![E(X)=0.4\times 0+0.4\times 1+0.2\times 2=0.8\\\\and Var[x]=E[x^2]-(E[x])^2\\\\E[x^2]=0\times 0.4+1\times 0.4+4\times 0.2=1.2\\\\So, Var[x]=1.2-(0.8)^2\\\\Var[x]=1.2-0.64=0.56](https://tex.z-dn.net/?f=E%28X%29%3D0.4%5Ctimes%200%2B0.4%5Ctimes%201%2B0.2%5Ctimes%202%3D0.8%5C%5C%5C%5Cand%20Var%5Bx%5D%3DE%5Bx%5E2%5D-%28E%5Bx%5D%29%5E2%5C%5C%5C%5CE%5Bx%5E2%5D%3D0%5Ctimes%200.4%2B1%5Ctimes%200.4%2B4%5Ctimes%200.2%3D1.2%5C%5C%5C%5CSo%2C%20Var%5Bx%5D%3D1.2-%280.8%29%5E2%5C%5C%5C%5CVar%5Bx%5D%3D1.2-0.64%3D0.56)
So, E[y]=2×0.8=1.6
and Var[y]=2×0.56=1.12
Hence, E(Y) = 1.6 and Var(Y)=1.12
Answer:
14p -3
Step-by-step explanation:
-7p 3(4p 2+3p - 1)
3x4= 12p
3x3=9p
12+9= 21
21-7=14p
3x2=6
3x-3=-9
-9 +6= -3
= 14p -3
hope this helps :)
Answer:
The answer is C. As you move closer to the center of the whirlpool, the speed of the current approaches infinity.
This means the closer you get, the faster you go, and the further the distance is the slower the speed. Hope this helps!
(Btw I got this right on the test)
We have to see the graph to what the answer is. Sorry I wish I could help!
For
ax+by=c
the slope is -a/b
20x+25y≥200
slope=-20/25=-4/5
negative slope
yint is where x=0
20(0)+25y≥200
25y≥200
y≥98
positive yint
x+y<10
slope=-1/1=-1
yint is where x=0
y<10
yint is at y=10
since it is equal, it is solid line
to tell if it is above then sub (0,0) and see if true
0≥200
false
shade on side that doesn't have (0,0), shade above line
x+y<10 doesn't have equal under so it is dashed
test (0,0)
0<10
true, it is shaded below
test point (4,5)
20(4)+25(5)≥200
80+125≥200
225≥200
true
4+5<10
9<10
true
so the ones that are true are
The line x + y < 10 has a negative slope and a positive y-intercept.
The line representing 20x + 25y ≥ 200 is solid and the graph is shaded above the line.
The overlapping region contains the point (4, 5).
