As a computer technician, Andre makes $20 per hour to diagnose a problem and $25 per hour to fix a problem. He works fewer than
10 hours per week, but wants to make at least $200 per week. The inequalities 20x + 25y ≥ 200 and x + y < 10 represent the situation. Which is true of the graph of the solution set? Check all that apply. The line 20x + 25y ≥ 200 has a positive slope and a negative y-intercept. The line x + y < 10 has a negative slope and a positive y-intercept. The line representing 20x + 25y ≥ 200 is solid and the graph is shaded above the line. The line representing x + y < 10 is dashed and the graph is shaded above the line. The overlapping region contains the point (4, 5).
For ax+by=c the slope is -a/b 20x+25y≥200 slope=-20/25=-4/5 negative slope
yint is where x=0 20(0)+25y≥200 25y≥200 y≥98 positive yint
x+y<10 slope=-1/1=-1 yint is where x=0 y<10 yint is at y=10
since it is equal, it is solid line to tell if it is above then sub (0,0) and see if true 0≥200 false shade on side that doesn't have (0,0), shade above line
x+y<10 doesn't have equal under so it is dashed test (0,0) 0<10 true, it is shaded below
test point (4,5)
20(4)+25(5)≥200 80+125≥200 225≥200 true
4+5<10 9<10 true
so the ones that are true are
The line x + y < 10 has a negative slope and a positive y-intercept. The line representing 20x + 25y ≥ 200 is solid and the graph is shaded above the line. The overlapping region contains the point (4, 5).
In order for an equation to be quadratic, the highest degree that is needed is two. The highest exponent provided is 3 therefore no it is not a quadratic function