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melisa1 [442]
2 years ago
6

ABC is a straight angle. Find m ABX and m CBX . (14x +70) (20x+8)​

Mathematics
1 answer:
IRISSAK [1]2 years ago
4 0

Answer:

ABX is 112 degrees.

CBX is 68 degrees.

Step-by-step explanation:

Angles on a straight line always add up to 180 degrees.

Thus,

(14x+70)+(20x+8)=180

Remove brackets:

14x+70+20x+8=180

Add up the terms:

34x+78=180

Subtract 78 from both sides:

34x+78-78=180-78

34x=102

Divide both sides by 34:

\frac{34x}{34}=\frac{102}{34}

x=3

Angle ABX = 14x+70=14(3)+70=42+70=112

Angle CBX =20x+8=20(3)+8=60+8=68

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T(5)=2\cdot5-7=3
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Does the type of program people watch influence how much they eat? A total of 94 college students were randomly assigned to one
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Answer:

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Find the surface area of the triangular prism. A triangular prism. The base is a right triangle with base 1 foot, height 2 feet
mylen [45]

Answer:

<h2>17.6ft²</h2>

Step-by-step explanation:

The formula for calculating the surface area of a triangular prism is expressed as shown below:

SA= bh + pH

b= base of the triangle

h- height of the triangle

p= perimeter of the triangle

H= height of the prism

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h = 2feet

perimeter of the triangle = sum of all its sides = 1ft + 2ft + 2.2ft

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Substituting the values into the formula for finding the surface area:

SA = 1(2)+5.2(3)

SA = 2+15.6

SA = 17.6ft²

The surface area of the triangular prism is  17.6ft²

3 0
2 years ago
Natasha uses 2.5 feet of twine to tie campfire wood into bundles. The proportional relationship between the number of bundles, x
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I am not sure but I think it represent the middle coordinate

4 0
1 year ago
15 Points!
goblinko [34]

Answer:

coordinate of point A is (a,b)

coordinate of point C is (2c,d)

slope of AD and BC =\frac{b}{a-c}

Step-by-step explanation:

According to midpoint formula

If we have points P (x_{1} ,y_{1} ) and Q (x_{2} ,y_{2} )

then the coordinate (x,y) of mid point of line PQ is given by

x=\frac{x_{1} +x_{2} }{2} and y=\frac{y_{1} +y_{2} }{2}

now from the given diagram A is the mid point of line joining  R(0,0) and S(2a,2b)

Using midpoint formula, coordinates of point A is given by

x=\frac{0+2a}{2}= a and y=\frac{0+2b}{2} =b

so we have

coordinate of point A is (a,b)

Also C is the midpoint of line joining T (2c,2d) and V(2c,0)

coordinate of point C is given by

x= \frac{2c+2c}{2} =2c and y=\frac{2d+0}{2} =d

so we have

coordinate of point C is (2c,d)

it is given that coordinate of point B is (a+c, b+d) and coordinate of D is (c,0)

If we have points P (x_{1} ,y_{1} ) and Q (x_{2} ,y_{2} )

then the slope of PQ =\frac{y_{2} -y_{1} }{x_{2}-x_{1}  }

hence slope of AD= \frac{0-b }{c-a}

                                 =\frac{-b}{c-a}

                                  =\frac{-b}{-(a-c)}

                                  =\frac{b}{a-c}

and slope of BC  =\frac{d-(b+d)}{2c-(a+c)}

                            =\frac{d-b-d}{2c-a-c}

                             =\frac{-b}{c-a}

                              =\frac{b}{a-c}

so we have

slope of AD and BC =\frac{b}{a-c}

7 0
2 years ago
Read 2 more answers
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