Answer:
a) MA conditional with C can be interpreted as A which is known and C which is unknown match
b) 10/11
c) 2/11
Step-by-step explanation:
A={A is the guilty party}
= {A blood type matches that of the guilty party}
C = {B is the guilty party}
= {B blood type matches that of the guilty party}
a) The chance is 10% because MA conditional with C can be interpreted as A which is known and C which is unknown match
b) the probability that A is the guilty party is given by 
. Using bayes theorem:
c) the probability that B’s blood type matches that of the guilty party is given as 
. Using LOTS Therefore:
Yes, 0.1 is less than 5.00.
5.00 is a whole number, while 0.1 is less than that, so yes, you were correct.
Have a nice day! :)
Answer: 17.3% of 45.94 km is 7.95 km
Answer:
(E) 0.83
Step-by-step explanation:
We will solve it using conditional probability.
Let A be the event that a TV show is successful.
P(A) = 0.5
A' be event that the show is unsuccessful
P(A') =0.5
Let B be the event that the response was favorable
P(B) = 0.6
Let B' be the event that the response was unfavorable/
P(B') = 0.4
P(A∩B) = 0.5 and P(A∩B') = 0.3
We need to find new show will be successful if it receives a favorable response.
P(A/B) = 
= 0.5/0.6
= 0.833
Answer:
a) 0.88
b) 0.35
c) 0.0144
d) 0.2084
e) 0.7916
Step-by-step explanation:
a) The probability of a peanut being brown is 12/100 = 0.12. Hence the probability of it not being brown is 1-0.12 = 0.88
b) 12% of peanuts are brown, 23% are blue. So 35% are either blue or brown. The probability of a peanut being blue or brown is, therefore 35/100 = 0.35.
c) 12% of peanuts are red, so the probability of a peanut being red is 12/100 = 0.12. In order to calculate the probability of 2 peanuts being both red, we can assume that the proportion doesnt change dramatically after removing one peanut (because the number of peanuts is absurdly high. We can assume that we are replenishing the peanuts). To calculate the probability of 2 peanuts being both red, we need to power 0.12 by 2, hence the probability is 0.12² = 0.0144.
d) Again, we will assume that the probability doesnt change, because we replenish. The probability of a peanut being blue is 0.23. The probability of it not being blue is 0.77, so the probability of 6 peanuts not being blue is obtained from powering 0.77 by 6, hence it is 0.77⁶ = 0.2084
e) The event 'at least one peanut is blue' is te complementary event of 'none peanuts are blue', so the probability of this event is 1- 0.2084 = 0.7916
