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Savatey [412]
2 years ago
11

Every day, Jorge buys a lottery ticket. Each ticket has a probability of of winning a prize. After six days, what is the probabi

lity that Jorge has won at least one prize? Round your answer to four decimal places.
Mathematics
1 answer:
Romashka [77]2 years ago
6 0

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Every day, Jorge buys a lottery ticket. Each ticket has a 0.16 probability of winning a prize. After six days, what is the probability that Jorge has won at least one prize? Round your answer to four decimal places.

Answer:

The probability that Jorge has won at least one prize after six days is

P(at least 1 win) = 0.6487

Step-by-step explanation:

Every day, Jorge buys a lottery ticket which has a 0.16 chance of winning a prize.

We want to find out the probability that Jorge has won at least one prize after six days.

P(at least 1 win) = 1 - P(not winning for 6 days)

We know that the probability of winning is 0.16 then the probability of not winning is

P(not winning) = 1 - 0.16 = 0.84

For 6 days,

P(not winning for 6 days) = 0.84×0.84×0.84×0.84×0.84×0.84

P(not winning for 6 days) = 0.84⁶

P(not winning for 6 days) = 0.3513

Finally,

P(at least 1 win) = 1 - P(not winning for 6 days)

P(at least 1 win) = 1 - 0.3513

P(at least 1 win) = 0.6487

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kupik [55]

Answer:

The answer is "She cut a total of 42 pieces of pie".

Step-by-step explanation:

Given :

Total pie=  5 \frac{1}{4}

cut pie = \frac{1}{8}

The number of pieces of the pie she has=?

Solve the mixed fraction value:

\to 5 \frac{1}{4}= \frac{21}{4}

If she cuts the pieces into the entire pie, that is  = \frac{1}{8}  

So, the equation is:

\to \frac{21}{4} = \frac{1}{8} \times x

\to x= \frac{21 \times 8}{4}\\\\ \to x= 21 \times 2\\\\ \to  x=42

7 0
1 year ago
If the code for CAB is DEK, what is the code for BED?
snow_tiger [21]

Answer:

CIM

Step-by-step explanation:

C is the 3rd letter of the alphabet, A is the 1st, and B is the 2nd.

CAB = 3,1,2

Repeating for DEK:

DEK = 4,5,11

Comparing:

4−3 = 1

5−1 = 4

11−2 = 9

BED = 2,5,4, so adding the corresponding numbers:

2+1 = 3

5+4 = 9

4+9 = 13

So the code is CIM.

7 0
2 years ago
In regional spelling bee, the 8 finalists consist of 3 boys and 5 girls. Find the number of sample point the sample space S for
Minchanka [31]

Answer:

i) There are 40320 possible orders

ii) There are 336 possible orders for the first 3 positions.

Step-by-step explanation:

Given: The number of finalists = 8

The number of boys = 3

The number of girls = 5

To find the number of sample point the sample space S for the number of possible orders, we need to find factorial of 8!

The number of possible orders = 8!

= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8

= 40320

ii) From all 8 finalist, we need to choose first 3 position. Here the order is important. So we use permutation.

nPr =\frac{n!}{(n - r)!}

Here n = 8 and r = 3

Plug in n =8 and r = 3 in the above formula, we get

8P3 = \frac{8!}{(8 - 3)!}

= \frac{8!}{5!} \\= \frac{1.2.3.4.5.6.7.8}{1.2.3.4.5}

= 6.7.8

= 336

So there are 336 possible orders for the first 3 positions.

3 0
2 years ago
George saves 18% of his total gross weekly earnings from his 2 part-time jobs. He earns $6.25 per hour from one part-time job an
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2 years ago
In ΔKLM, the measure of ∠M=90°, LK = 89, ML = 80, and KM = 39. What ratio represents the tangent of ∠K?
vodka [1.7K]

<u>Given</u>:

It is given that KLM is a right triangle.

The measure of ∠M is 90°

The length of LK is 89, ML is 80 and KM is 39.

We need to determine the ratio that represents the tangent of ∠K.

<u>Measure of tan ∠K:</u>

The measure of tan ∠K can be determined using the trigonometric ratio.

Thus, we have;

tan \ \theta=\frac{opp}{adj}

From the figure attached below, the side opposite to ∠K is ML and the side adjacent to ∠K is KM

Hence, substituting the values, we get;

tan \ k=\frac{ML}{KM}

where ML = 80 and KM = 39.

Substituting, we get;

tan \ k=\frac{80}{39}

Thus, the ratio that represents the tangent of ∠K is \frac{80}{39}

3 0
1 year ago
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