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2 years ago

7

The equation y = 14x represents the number of pages Printer A can print over time, where y is the number of pages and x is time

in minutes. The table shows the number of pages Printer B can print over time.
How many pages does each printer print per minute, and which printer prints at a faster rate?

Printer A:[ ]pages per minute

Printer B:[ ]pages per minute

The printer that prints at a faster rate is Printer[ ]. (Type A for Printer A or B for Printer B)

2 answers:

Crank2 years ago

8 0

Printer A
y = 14x

Printer B
Time(min) | 3 | 5 | 8 | 12 |
Pages printed | 48 | 80 | 128 | 192 |

Printer A prints 14(1) = 14 pages per minute.
Printer B prints 48/3 = 16 pages per minute.

The printer that prints at a faster rate is printer B.

Bingel [31]2 years ago

3 0

Answer:

Printer A: 14 pages per minute

Printer B: 16 pages per minute

The printer that prints at a faster rate is Printer B.

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If f (x) = 5 x minus 25 and g (x) = one-fifth x + 5, which expression could be used to verify g(x) is the inverse of f(x)?

Vinil7 [7]

Answer:

The expression used to represent g(x) as inverse of f(x) is $\frac{1}{5}(5x-25)+5$

Option B is correct.

Step-by-step explanation:

We are given:

$f(x)= 5x-25\\g(x)=\frac{1}{5}x+5$

We need to find the expression that could be used to verify g(x) is the inverse of f(x).

We know that $g(f(x))=x$ is inverse of function

So placing value of f(x) in g(x)

$g(f(x))=\frac{1}{5}(5x-25)+5$

So, the expression used to represent g(x) as inverse of f(x) is $\frac{1}{5}(5x-25)+5$

Option B is correct.

We can also solve to prove that $g(f(x))=x$

$g(f(x))=\frac{1}{5}(5x-25)+5\\g(f(x))=\frac{5}{5}(x-5)+5\\g(f(x))=x-5+5\\g(f(x))=x$

5 0

1 year ago

Read 2 more answers

What is the quotient (3x4 – 4x2 + 8x – 1) ÷ (x – 2) brainly

Karolina [17]

To find our quotient we are going to perform long division.

Long division step by step:

Step 1. Write the polynomial (dividend) in descending order (from highest to least exponent). If you encounter a missing term, use zero to fill the space of the term in the descending sequence.

Notice that even tough our polynomial is written in descending form, $x^3$ is missing, so we are going to use $0x^3$ to fill the gap:

$3x^4-4x^2+8x-1$

$3x^4+0x^3-4x^2+8x-1$

Step 2. Divide the first term of the polynomial (dividend) by the first term of the divisor.

In our case the first term of the dividend is $3x^4$ and the first term of the divisor is $x$ , so $\frac{3x^4}{x} =3x^3$ . Notice that $3x^3$ is the first term of the quotient.

Step 3. Multiply the first term of the quotient by the terms of the divisor and subtract them from the respective term of the dividend.

The first term of our quotient (from the previous step) is $3x^3$ and the divisor is $(x-1)$ , so $3x^3(x-2)=3x^4-6x^3$ . Now, we are going to subtract them from the respective term (the term with the same power) of the dividend. The respective terms of the dividend are $3x^4$ and $0x^3$ , so $3x^4-3x^4=0$ and $0x^3-(-6x^3)=0x^3+6x^3=6x^3$

Step 4. Bring down the next term in the dividend and repeat the process for the remaining terms.

After finish the process (check the attached picture), we can conclude that the quotient of $3x^4-4x^2+8x-1$ ÷ $(x-2)$ is $3x^3+6x^2+8x+24$ with a remainder of $47$ , or in a different notation: $3x^3+6x^2+8x+24+\frac{47}{x-2}$

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2 years ago

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A company produces and sells 211,600 boxes of t-shirts each year. Each production run has a fixed cost of $400 and an additional

Illusion [34]

Answer: $x=46$

Step-by-step explanation:

Given

Company Produces and sells 211600 boxes of T-shirt each year

Fixed cost =$ 400

Additional cost = $ 3 per box

storage cost =$ 2

let x be the no of production run

therefore

Holding cost per year $=holding\ cost\times average\ holding\ items=2\times \frac{211600}{2x}=\frac{211600}{x}$

$Yearly\ ordering\ cost=cost\ during\ each\ order\times number\ of\ order\ Placed\ per\ year$

yearly ordering cost $=400x+3\times \frac{211600}{x}$

Total cost C(x) $=\frac{211600}{x}+400x+3\times \frac{211600}{x}$

differentiate C(x) w.r.t to x we get

$\frac{\mathrm{d} C(x)}{\mathrm{d} x}=400-\frac{3\times 211600}{x^2}-\frac{1}{211600}$

Put $\frac{\mathrm{d} C(x)}{\mathrm{d} x}=0$ to get max/min value

$400-\frac{211600}{x^2}-\frac{3\times 211600}{x^2}=0$

$x^2=\frac{211600}{100}$

$x=\sqrt{2116}$

$x=46$

therefore 46 runs must be performed

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1 year ago

Paul owns a gym and needs to replace the carpeting on the floor. The gym's floor plan is shown.

zubka84 [21]

Answer:

<em>24 square yards</em>

Step-by-step explanation:

Find the diagram attached.

The area of the diagram = Area of rectangle + Area of triangle

Area of rectangle = 3 * 4

Area of rectangle = 12 square yards

Area of triangle = 1/2 * base * height

Area of triangle = 1/2 * 6 * 4

Area of triangle = 12 square yards

Area of the diagram = 12 + 12

Area of diagram = 24 square yards

<em>Hence 24 square yards of carpeting is needed</em>

7 0

1 year ago

A new car is purchased for 15300 dollars. The value of the car depreciates at 14.25% per year. What will the value of the car be

Andrei [34K]

Answer:

$\$6,082.70$

Step-by-step explanation:

we know that

The formula to calculate the depreciated value is equal to

$V=P(1-r)^{x}$

where

V is the depreciated value

P is the original value

r is the rate of depreciation in decimal

x is Number of Time Periods

in this problem we have

$P=\$15,300\\r=14.25\%=0.1425\\x=6\ years$

substitute in the formula

$V=15,300(1-0.1425)^{6}$

$V=15,300(0.8575)^{6}$

$V=\$6,082.70$

3 0

2 years ago