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trasher [3.6K]
2 years ago
13

Triangle KLM represents a section of a park set aside for picnic tables. The picnic area will take up approximately 400 square y

ards in the park.
To the nearest yard, what amount of fencing is needed to surround the perimeter of the picnic area?

95 yards
107 yards
160 yards
190 yards
Mathematics
2 answers:
zubka84 [21]2 years ago
8 0

Answer:

B. 107 yards

Step-by-step explanation:

Going off the correction in the comments of the first answer lol.

svetoff [14.1K]2 years ago
6 0
Given triangle KLM with two sides given as 45 yd and 20 yd and a 25 degree angle opposite the 20 yd side.

We find the angle made at the opposite of the 45 yd side using the sine rule as follows.
\frac{\sin{A}}{a} =  \frac{\sin{B}}{b}  \\  \frac{\sin{25^o}}{20} = \frac{\sin{B}}{45}  \\ \sin{B}= \frac{45\sin{25^o}}{20} = \frac{19.0178}{20} =0.9509 \\ B=\arcsin{(0.9509)}=71.97^o

Thus, the third angle is given by 180 - 25 - 71.97 = 83.03 degrees.

We also use the sine rule to find the third side of the triangle as follows.
\frac{\sin{A}}{a} = \frac{\sin{C}}{c} \\ \frac{\sin{25^o}}{20} = \frac{\sin{83.03^o}}{c} \\ c= \frac{20\sin{83.03^o}}{\sin{25^o}} = \frac{19.8522}{\sin{25^o}} =46.97 yds

Therefore, amount of fencing needed to surround the perimeter of the picnic area = 45 + 20 + 46.97 = 111.97 ≈ 120 yds
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Alisiya [41]

Answer:

C. Stacy

Step-by-step explanation:

One way to compare is to convert all the fractions into decimals

    Rachel works 2/3 of her shift: Approximately= 0.667

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    Damon works 4/5= 0.80

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Now this makes it much easier to compare

And since 0.85714 (Stacy's shift) is the largest number, Stacy has completed the largest portion of her shift

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2 years ago
A wheat farmer cuts down the stalks of wheat and gathers them in 200 piles. The 200 gathered piles will be put on a truck. The t
denpristay [2]

Answer:

Check the explanation

Step-by-step explanation:

We want to estimate the total weight of grain on the field based on the data on a simple random sample of 5 piles out of 200. The population and sample sizes are N=200 & n=5 respectively.

1) Let Y_1,Y_2,...,Y_{200} be the weight of grain in the 200 piles and y_1,y_2,...,y_{5} be the weights of grain in the pile from the simple random sample.

We know, the sample mean is an unbiased estimator of the population mean. Therefore,

\widehat{\mu}=\overline{y}=\frac{1}{5}\sum_{i=1}^{5}y_i=\frac{1}{5}(3.3+4.1+4.7+5.9+4.5)=4.5

where \mu is the mean weight of grain for all the 200 piles.

Hence, the total grain weight of the population is

\widehat{Y}=Y_1+Y_2+...+Y_{200}

=200\times \widehat{\mu}\: \: \: =200\times 4.5\: \: \: =900\, lbs

2) To calculate a bound on the error of estimates, we need to find the sample standard deviation.

The sample standard deviation is

 S=\sqrt{\frac{1}{5-1}\sum_{i=1}^{5}(y_i-\overline{y})^2}\: \: \: =0.9486

Then, the standard error of \widehat{Y} is

\sigma_{\widehat{Y}} =\sqrt{\frac{N^2S^2}{n}\bigg(\frac{N-n}{N}\bigg)}\: \: \:=83.785

Hence, a 95% bound on the error of estimates is

[\pm z_{0.025}\times \sigma_{\widehat{Y}}]\: \: \: =[\pm 1.96\times 83.875]\: \: \: =[\pm 164.395]

3) Let x_1,x_2,...,x_5 denotes the total weight of the sampled piles.

Mean total weight of the sampled piles is

\overline{x}=\frac{1}{5}\sum_{i=1}^{5}x_i=45

The sample ratio is

r=\frac{\overline{y}}{\overline{x}}=\frac{4.5}{45}=0.1 , this is also the estimate of the population ratio R=\frac{\overline{Y}}{\overline{X}} .

Therefore, the estimated total weight of grain in the population using ratio estimator is

\widehat{Y}_R\: \: =r\times 8800\: \: =0.1\times 8800\: \: =880\, lbs

4) The variance of the ratio estimator is

var(r)=\frac{N-n}{N}\frac{1}{n}\frac{1}{\mu_x^2}\frac{\sum_{i=1}^{5}(y_i-rx_i)^2}{n-1}   , where \mu_x=8800/200=44lbs

=\frac{200-5}{200}\, \frac{1}{5}\: \frac{1}{44^2}\, \frac{0.2}{5-1}=0.000005

Hence, the standard error of the estimate of the total population is

\sigma_R=\sqrt{X^2 \: var(r)}\: \: \: =\sqrt{8800^2\times 0.000005}\: \: \:=21.556

Hence, a 95% bound on the error of estimates is

[\pm z_{0.025}\times \sigma_{R}]\: \: \: =[\pm 1.96\times 21.556]\: \: \: =[\pm 42.25]

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Answer:

Joint variation says that:

if x \propto y and x \propto z

then the equation is in the form of:

x = kyz, where, k is the constant of variation.

As per the statement:

If x varies jointly as y and z

then by definition we have;

x=k(yz)           ......[1]

Solve for k;  

when x = 8 , y=4 and z=9

then

Substitute these in [1] we have;

8=k(4 \cdot 9)

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Divide both sides by 36 we have;

\frac{8}{3}=k

Simplify:

k = \frac{2}{9}

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Substitute these value we have;

16 = \frac{2}{9} \cdot 6 \cdot z

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144 = 12z

Divide both sides by 12 we have;

12 = z

or

z = 12

Therefore, the value of z is, 12

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2 years ago
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Naya [18.7K]

Answer:

99m

Step-by-step explanation:

multiply the two numbers

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Which lines are parallel if M^4 +M^5? Justify your answer.
Igoryamba
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