Answer:
The null hypothesis is that all the different teaching methods have the same average test scores.
H0: μ1 = μ2 = μ3 = μ4 = μ5
The alternative hypothesis is that at least one of the teaching methods have a different mean.
Ha: at least one mean is different. (μ1 ≠ μi)
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
For the case above, let μ represent the average test scores for the teaching methods:
The null hypothesis is that all the different teaching methods have the same average test scores.
H0: μ1 = μ2 = μ3 = μ4 = μ5
The alternative hypothesis is that at least one of the teaching methods have a different mean.
Ha: at least one mean is different. (μ1 ≠ μi)
Answer: <em><u>C. the base period amount.</u></em>
<u><em>Explanation: </em></u>While implementing a horizontal analysis on a given income statement, we compute a percentage change in any individual item by dividing the dollar amount of change from base to current time period with <u><em>the base period amount.</em></u>
i.e. % Change in Individual item = 
<u><em>Therefore, the correct option in this case is (c)</em></u>
Answer:
m=24
Explanation: 120/5=24 just caculate it.
Answer:
D(t) = 3 + 0.0(80 - t)
Step-by-step explanation:
The average of speed of Laura in miles per hour is given by:
S(t) = 6 + 0.1(80 - t) Equation 1
where, t is the temperature in degrees Fahrenheit.
The distance D, Laura covers at x miles per hour is given as:
D(x) = 0.5x Equation 2
We need to find the expression that models the distance that Laura runs in terms of the temperature "t"
The "x" in Equation 1 represents the average speed of Laura in miles per hour. S(t) in Equation 1 also represent the speed of Laura in miles per hour. So, we can replace x by S(t) in Equation 2 and generate an equation of Distance in terms of temperature "t" as shown below:
D(S(t)) = 0.5 (6 + 0.1(80-t))
D(t) = 3 + 0.0(80 - t)
This expression models the distance that Laura runs in 30 minutes given that it is t∘F outside at the start of her run.