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NikAS [45]
2 years ago
9

PLS HELP ILL MARK U BRAINLIEST The graph below shows a company's profit f(x), in dollars, depending on the price of pencils x, i

n dollars, sold by the company:
Graph of quadratic function f of x having x intercepts at ordered pairs negative 0, 0 and 10, 0. The vertex is at 5, 160.

Part A: What do the x-intercepts and maximum value of the graph represent? What are the intervals where the function is increasing and decreasing, and what do they represent about the sale and profit? (4 points)

Part B: What is an approximate average rate of change of the graph from x = 2 to x = 5, and what does this rate represent? (3 points)

Part C: Describe the constraints of the domain. (3 points)
Mathematics
1 answer:
BartSMP [9]2 years ago
4 0

Answer:Part A) see the explanation

Part B) see the explanation

Step-by-step explanation:

The picture of the question in the attached figure

Part A: What do the x-intercepts and maximum value of the graph represent? What are the intervals where the function is increasing and decreasing, and what do they represent about the sale and profit?

Let

x ----> the price of pencils in dollars

f(x) ----> a company's profit in dollars

we know that

The function f(x) is a quadratic function having x-intercepts at (0,0) and (10,0)

The x intercepts give us the price when profit is zero, so the x-intercepts represent break-even points

The vertex is at (5,160)

f(x) represent a vertical parabola open downward

The vertex is a maximum

The x-coordinate of the vertex represent the price of the pencils when the value of the profit is maximum

The y-coordinate of the vertex represent the maximum profit

therefore

The maximum profit of $160 is when the price of the pencils is $5

Profit is increasing on the interval (0,5) and decreasing on the interval (5,10)

This represents that profit is increasing when selling price ranges from 0 dollars to 5 dollars, then decreases when selling price is 5 dollars to 10 dollars

Part B: What is an approximate average rate of change of the graph from x = 2 to x = 5, and what does this rate represent?

Find the average rate of change of the graph from x = 2 to x = 5

To find the average rate of change, we divide

Step-by-step explanation:

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Nathan flew 3,547 miles from Canada to California during the first part of his trip. He flew 2,567 miles from California to Hawa
AURORKA [14]

Difference in the number of miles Nathan flew between the first and second parts of his trip is 980 miles

<em><u>Solution:</u></em>

Given that Nathan flew 3,547 miles from Canada to California during the first part of his trip

He flew 2,567 miles from California to Hawaii during the second part of his trip

Therefore,

first part of his trip = 3547 miles

second part of his trip = 2567 miles

Difference in the number of miles Nathan flew between the first and second parts of his trip is given as:

difference = first part of his trip - second part of his trip

difference = 3547 - 2567 = 980

Therefore, the difference in number is 980 miles

4 0
2 years ago
A local pizzeria offers 15 toppings for their pizzas and you can choose any 3 of them for one fixed price. How many different ty
Shtirlitz [24]

Answer:

  455 or 680, depending

Step-by-step explanation:

If we assume the three choices are different, then there are ...

  15C3 = 15·14·13/(3·2·1) = 35·13 = 455

ways to make the pizza.

___

If two or three of the topping choices can be the same, then there are an additional ...

  2(15C2) +15C1 = 2·105 +15 = 225

ways to make the pizza, for a total of ...

  455 + 225 = 680

different types of pizza.

__

There is a factor of 2 attached to the number of choices of 2 toppings, because you can have double anchovies and tomato, or double tomato and anchovies, for example, when your choice of two toppings is anchovies and tomato.

_____

nCk = n!/(k!(n-k)!)

6 0
2 years ago
A pilot was scheduled to depart at 4:00 pm, but due to air traffic, her departure has been delayed by 10 minutes. Air traffic co
alexandr402 [8]

Answer:

a. y equals one third times x plus 10

= y = 1/3(x) + 10

Step-by-step explanation:

Let us represent:

Let the original final plan = x

Let the current flight plan = y

The initial time of departure = 4.00pm

Her flight was then delayed for 10 minutes

We are told in the question that:

The current flight plan allows her arrive at her destination three times faster.

This means y= (1/3)x

y = x/3

Hence the equation generated =

y = x/3 +10

y = 1/3(x) + 10

4 0
2 years ago
Suppose a shipment of 400 components contains 68 defective and 332 non-defective computer components. From the shipment you take
MrRissso [65]

Answer:

mean (μ) = 4.25

Step-by-step explanation:

Let p = probability of a defective computer components = \frac{68}{400} = 0.17

let q = probability of a non-defective computer components = \frac{332}{400} = 0.83

Given random sample n = 25

we will find mean value in binomial distribution

The mean of binomial distribution = np

here 'n' is sample size and 'p' is defective components

mean (μ) = 25 X 0.17 = 4.25

<u>Conclusion</u>:-

mean (μ) =  4.25

6 0
2 years ago
Melissa wants to make a table representing the area of her vegetable garden for a variety of different lengths of the tomato pat
Ksenya-84 [330]

Answer:

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

Step-by-step explanation:

The date from the given table, is expressed as follows;

Area of Vegetable Garden (in square feet); 338, ___, 147.25, ___

Length of Tomato Patch (in feet); ___, 6.5, ___, 7

The length of the tomato patch increases with decrease in the area of the garden

Given that the length of the tomato patch is the independent variable, we can have;

Length of Tomato Patch (in feet); 6.25, 6.5, 6.75, 7

Therefore, for an increase in the length of the tomato patch from 6.25 to 6.75, (a change of Δl = 0.5) the area of the vegetable garden decreased from 338 to 147.25 which is a decrease of ΔA = 190.75

Therefore, the width of the tomato patch, w = ΔA/Δl = 190.75/0.5 = 381.5

The width of the tomato patch, w = 381.5 ft.

The relationship between the total area, TA, the area of the vegetable garden, <em>A</em>, and the length of the tomato patch, <em>l</em>, is therefore, given as follows;

A = TA - 381.5·l

338 = TA - 381.5×6.25

TA = 338 + 381.5×6.25 = 2,722.375

Therefore, when l = 6.5, we get

A = 2,722.375 - 381.5×6.5 = 242.625

When l = 7, we get

A = 2,722.375 - 381.5×7 = 51.875

Therefore, we get;

\begin{array}{cc}Length \ of \ Tomato \ Patch \ (in \ feet)&Area \ of \ Vegetable \ Garden \ (in  \ square \ feet)\\\ [6.25]&338\\6.5&[242.625]\\  \ [6.75]&147.25\\7&[51.875]\end{array}

5 0
1 year ago
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