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Olin [163]
2 years ago
11

If f Superscript negative 1 Baseline (x) = negative one-fifth x, what is f Superscript negative 1 Baseline (x) = one-fifth x?

Mathematics
2 answers:
Amanda [17]2 years ago
8 0

Answer:

A different inverse function

Step-by-step explanation:

Artyom0805 [142]2 years ago
5 0

Answer:

  a different inverse function

Step-by-step explanation:

If f^{-1}(x)=-\frac{1}{5}x then f^{-1}(x)=\frac{1}{5}x is a different inverse function.

__

The second (inverse) function is the first reflected over the y-axis.

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There are exactly π radians in a semicircle. There are exactly π radians in a full circle. There are approximately radians in a
Allisa [31]

pi radians in a semicircle (half circle)

2pi radians in a full circle.

2pi = 2*3.14 = 6.28 approximately, so there are approximately 6.28 radians in a half circle.

2pi radians is equivalent to 360 degrees.


8 0
2 years ago
Read 2 more answers
Modern Vehicles Company came up with two different plans for the next financial year. Plan Y: Increase vehicle production by 5%
ladessa [460]

Answer: plan Y will produce more vehicles after 4 years.

Step-by-step explanation:

1) Plan Y: Increase vehicle production by 5% every year. It means that the rate of production is in geometric progression. The formula for determining the sum of n terms, Sn of a geometric sequence is expressed as

Sn = (ar^n - 1)/(r - 1)

Where

n represents the number of term(years) in the sequence.

a represents the first term(number of vehicles in the present year) in the sequence.

r represents the common ratio.

From the information given,

a = 10000

r = 1 + 5/100 = 1.05

n = 4 years

Therefore, the sum of the vehicles produced in the first 4 years, S4 is

S4 = (10000 × 1.05^(4) - 1)/1.05 - 1

S4 = (10000 × 0.21550625)/0.05

S4 = 2155.0625/0.05

S4 = 43101 vehicles

2) Plan Z: Increase production by 300 vehicles every year. It means that the rate of production is in geometric progression. The formula for determining the sum of n terms of an arithmetic sequence is expressed as

Sn = n/2[2a + (n - 1)d]

Where

n represents the number of terms in the arithmetic sequence.

d represents the common difference of the terms in the arithmetic sequence.

a represents the first term of the arithmetic sequence.

From the information given,

n = 4 years

a = 10000

d = 300

Therefore, the sum of the first 4 terms, S4 would be

S4 = 4/2[10000 × 2 + (4 - 1)300]

S4 = 2[20000 + (3)300]

S4 = 2 × 20900

S4 = 41800 vehicles

6 0
2 years ago
A pendulum is set swinging. its first oscillation is through 30 and each succeeding oscillation is through 95% of the angle of t
Marat540 [252]

<u>Answer-</u>

<em>After 76 swings</em><em> the angle through which it swings less than 1°</em>

<u>Solution-</u>

From the question,

Angle of the first of swing = 30° and then each succeeding oscillation is through 95% of the angle of the one before it.

So the angle of the second swing = (30\times \frac{95}{100})^{\circ}

Then the angle of third swing = (30\times (\frac{95}{100})^2)^{\circ}

So, this follows a Geometric Progression.

(30,\ 30\cdot \frac{95}{100},\ 30\cdot (\frac{95}{100})^2............,0)

a = The initial term = 30

r = Common ratio = \frac{95}{100}

As we have to find the number swings when the angle swept by the pendulum is less than 1°.

So we have the nth number is the series as 1, applying the formula

T_n=ar^{n-1}

Putting the values,

\Rightarrow 1=30(\frac{95}{100})^{n-1}

\Rightarrow \frac{1}{30} =(\frac{95}{100})^{n-1}

Taking logarithm of both sides,

\Rightarrow \log \frac{1}{30} =\log (\frac{95}{100})^{n-1}

\Rightarrow \log \frac{1}{30} =(n-1)\log (\frac{95}{100})

\Rightarrow -1.5=(n-1)(-0.02)

\Rightarrow 1.5=(n-1)(0.02)

\Rightarrow n-1=\dfrac{1.5}{0.02}

\Rightarrow n-1=75

\Rightarrow n=76

Therefore, after 76 swings the angle through which it swings less than 1°

8 0
2 years ago
Heidi is saving for a new bike. She has already saved $57. If Heidi earns
PtichkaEL [24]

Answer:

8 hours

Step-by-step explanation:

57 + 9h = 129

9h = 72

h = 8

7 0
2 years ago
Read 2 more answers
Here are the monthly charges for jo’s Mobile phone. Monthly charge £16,150 free minutes,then 13p per minute,150 free texts,then
zhuklara [117]

Answer:

16,652

Step-by-step explanation:

5 0
2 years ago
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