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xz_007 [3.2K]
1 year ago
14

g A sailing ship stopped at several islands, releasing one mating pair of goats onto each one. On the large island, the goats' g

rowth rate was approximately exponential for a long time. If their per capita growth rate is 0.5 per year, how many years will it take before the goat population reaches 1000
Mathematics
2 answers:
PSYCHO15rus [73]1 year ago
5 0

Answer:

The goat population reaches 1000 in 12.4 years

Step-by-step explanation:

After <em>t </em>years, the number of goats is given by

N = N_0e^{bt}

where N_0 is the initial number of goats and <em>b</em> is the per capita growth rate.

From the question,

  • N_0 = 2
  • <em>b</em> = 0.5
  • <em>N</em> = 1000

1000 = 2e^{0.5t}

e^{0.5t} = 500

0.5t = \ln 500 = 6.214

t = \dfrac{6.2}{0.5} = 12.4

Serggg [28]1 year ago
4 0

Answer:

12.4 years  

Step-by-step explanation:

Let recall the following,

The number of goats after t years is shown below

N = N₀∧ebt

Let N₀ = the number of the initial goats

b = The capital rate of growth

From the example given,

Let insert the values

N₀ is = 2

b = 0.5

Let N = 1000

So,

1000= 2e∧0.5t

e∧0.5t = 500

0.5t = ln 500 = 6.214

Therefore

t = 6.214/0.5 =12.4

Therefore, the number of years it will take for the goat population to reach 1000 is = 12.4 years  

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2 years ago
A map of Colorado says that the scale is 1 inch to 20 miles or 1 to 1,267,200. Are these two ways of reporting the scale the sam
goldenfox [79]

Answer:

1,267,200

Step-by-step explanation:

Given that the map reported that the scale is 1 inch to 20 miles.

Recall that there are 63,360 inches in 1 mile, thus, in 20 miles, we have 20 x 63,360 = 1,267,200

Therefore, the scale of 1 inch to 20 miles can also be represented as 1 to 1,267,200

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1 year ago
Joanna pays $40 plus a $2 surcharge each month for her high-speed Internet service. Which table BEST represents the relationship
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can you show the tables ?

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1 year ago
A study was performed on green sea turtles inhabiting a certain area.​ Time-depth recorders were deployed on 6 of the 76 capture
polet [3.4K]

Answer:

One can be 99% confident the true mean shell length lies within the above interval.

The population has a relative frequency distribution that is approximately normal.

Step-by-step explanation:

We are given that Time-depth recorders were deployed on 6 of the 76 captured turtles. These 6 turtles had a mean shell length of 51.3 cm and a standard deviation of 6.6 cm.  

The pivotal quantity for a 99% confidence interval for the true mean shell length is given by;

                    P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean shell length = 51.3 cm

             s = sample standard deviation = 6.6 cm

             n = sample of turtles = 6

             \mu = true mean shell length

Now, the 99% confidence interval for \mu =  \bar X \pm t_(_\frac{\alpha}{2}_)  \times \frac{s}{\sqrt{n} }

Here, \alpha = 1% so  (\frac{\alpha}{2}) = 0.5%. So, the critical value of t at 0.5% significance level and 5 (6-1) degree of freedom is 4.032.

<u>So, 99% confidence interval for</u> \mu  =  51.3 \pm 4.032 \times \frac{6.6}{\sqrt{6} }

                                                         = [51.3 - 10.864 , 51.3 + 10.864]

                                                         = [40.44 cm, 62.16 cm]

The interpretation of the above result is that we are 99% confident that the true mean shell length lie within the above interval of [40.44 cm, 62.16 cm].

The assumption about the distribution of shell lengths must be true in order for the confidence interval, part a, to be valid is that;

C. The population has a relative frequency distribution that is approximately normal.

This assumption is reasonably satisfied as the data comes from the whole 76 turtles and also we don't know about population standard deviation.

3 0
1 year ago
a direct variation function contains the points ( -8, -6 ) and (12,9 ) . Which equation represents the function ?
9966 [12]

Answer:

y = \frac{3}{4} x

Step-by-step explanation:

Given that the quantities vary directly then the equation relating them is

y = kx ← k is the constant of variation

To find k use either of the 2 given points

Using (12, 9), that is x = 12 when y = 9, then

k = \frac{y}{x} = \frac{9}{12} = \frac{3}{4}

y = \frac{3}{4} x ← equation of variation

8 0
1 year ago
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