(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.
Answer: D. 41 cm
There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,
a^2+b^2 = (b+1)^2
a^2 + b^2 = b^2 + 2b +1
a^2=2b+1
So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.
b = (a^2 - 1)/2
a=3, b=(3^2-1)/2=4, c=b+1=5
a=5, b=(5^2-1)/2 =12, c = 13
a=7, b=24, c=25
a=9, b=40, c=41
a=11, b=60, c=61
a=13, b=84, c=85
It's good to be able to recognize Pythagorean Triples when we see them.
Otherwise we'd have to work the calculator:
√(9² + 40²) = √1681 = 41
If the first expression reads x(cube) • x(cube) • x(cube) and x(cube • cube <span>• cube), then the answer is no. They are not equal.
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x(cube) • x(cube) <span>• x(cube) will be equivalent to x(to the 9th power) while </span>x(cube • cube <span>• cube) will be equivalent to x( to the 27th power). </span><span>
</span>
So the ratio is 1 to 2 to 5
so basically 1 unit of soda water to 2 units of fruit punch to 5 units of ginger ale
total is 1+2+5=8 units
so 4 gallons=8 units
divide by 8
1/2 gallon=1 unit
soda water=1 unit=1/2 gallon
fruit punch=2 unit=1/2 times 2=1 gallon
ginger ale=5 unit=5 times 1/2=5/2=2 and 1/2 gallon
soda water=1/2 gallon
fruit punch concentrate=1 gallon
ginger ale=5/2 gallon or 2 and 1/2 gallon
Given an exponential function, say f(x), such that f(0) = 1 and f(1) = 2 and a quadratic finction, say g(x), such that g(0) = 0 and g(1) = 1.
The rate of change of a function f(x) over an interval

is given by

Thus, the rate of change (growth rate) of the exponential function, f(x) over the interval

is given by

Similarly, the rate of change (growth rate) of the quadratic function, g(x) over the interval

is given by

Therefore, the exponential grows at the same rate as the quadratic in the interval <span>

.</span>
Answer:
D
Step-by-step explanation:
In order to find the midpoint of a line segment on a graph, you must add both "x" coordinates, then divide by 2.
Then, add both "y" coordinates, and divide by 2.