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Savatey [412]
2 years ago
6

The price of an article is Rs 1200 and a customer pays Rs 1380 with VAT. Find the rate of VAT​

Mathematics
1 answer:
garik1379 [7]2 years ago
8 0

Answer:

15%

Step-by-step explanation:

vat amount

= 1380 - 1200

=180

finding the rate of vat

= 1380/1200 *100

= 115%

NB : the 115% shows that 1200 8 115% = 1380 , this give total amount including vat , we only want vat hence we have to deduct the 100% which indicates the amount of article)

hence 115 - 100 = <u>15%</u>

15% * 1200= 180

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1.8 miles

Step-by-step explanation:

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2 years ago
Given that the two parallel lines are cut by a transversal, and the measure of angle 2 is 50 degrees. Find each of the missing a
Mandarinka [93]

Answer:

Step-by-step explanation:

Lines m and l are the parallel lines and a line 'n' is a transverse intersecting these lines.

m∠2 = 50°

m∠1 + m∠2 = 180° [Linear pair of angles]

m∠1 = 180° - 50°

m∠1 = 130°

m∠3 = m∠1 = 130° [Vertically opposite angles]

m∠3 + m∠5 = 180° [Consecutive interior angles]

m∠5 = 180° - m∠3

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        = 50°

m∠6 + m∠5 = 180° [Linear pair of angles]

m∠6 = 180° - 50° = 130°

7 0
2 years ago
Let ff be the function given by f(x)=e2x−1 x f(x)=e2x−1 x. Which of the following equations expresses the property that f(x)f(x)
navik [9.2K]

Answer:

Step-by-step explanation:

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5 0
2 years ago
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A student wants to know how far above the ground the top of a leaning flagpole is. At high​ noon, when the sun is almost directl
MariettaO [177]

Answer:

15.43 ft

Step-by-step explanation:

To solve this question, one should use the concept of similar triangles.

The pole's shadow and the distance to the ground (x) form a similar triangle to the distance of the plumb bob from the base and the length of the plumb bob, respectively. Note that we do not need to know the measurements of the third side of the triangles to solve the problem.  Therefore, the distance of the top of the pole to the ground is:

14 in = 1.1667 ft

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The distance of the top of the pole to the ground is 15.43 ft.

4 0
2 years ago
Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting
stealth61 [152]

Answer:

Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j} and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

Ann walk as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

Thus, Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

 




7 0
2 years ago
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