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victus00 [196]
2 years ago
13

Click to select the figure in the image that would portray the rotation of the given preimage and the rotation arrow,

Mathematics
1 answer:
LekaFEV [45]2 years ago
8 0

Answer:

plz explain correctly please

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Solve 7x- c= k for x. <br>A. X = 7(k+C) <br>B. x = 7(K-C) <br>C. X = k+c/7 <br>D. X= k-c/7​
antoniya [11.8K]

Answer:

C

Step-by-step explanation:

you add c to both side which will then make it 7x=k+c then you would divide 7 from both sides leaving you with x=k+c/7. Except 7 will be under the k and c.

7 0
1 year ago
PLZZZZZZ HELP WILL GIVE BRAINLEST
jonny [76]

−7⋅(−3)⋅(−9)⋅(−3)

21 * -9 * -3

-189 * -3

567

Choice D

4 0
2 years ago
Read 2 more answers
In ΔVWX, x = 5.3 inches, w = 7.3 inches and ∠W=37°. Find all possible values of ∠X, to the nearest 10th of a degree.
STALIN [3.7K]

Answer:

que?

Step-by-step explanation:

4 0
1 year ago
Read 2 more answers
A freight company has shipping orders for two products. The first product has a unit volume of 10 cu ft, and it weighs 50 lbs. T
Lady_Fox [76]

Answer:

116 units of the first product

380 units of the second product

Step-by-step explanation:

Product 1 has a unit volume of  10 cu ft

Product 2 has a unit volume of 3 cu ft

The truck has 2300 cu ft of space

Product 1 weighs 50 lbs

Product 2 weighs 40 lbs

The truck can carry 21000 lbs

Let X be the units of product 1

Let Y be the units of product 2

The given information can be expressed as:

10X+3Y=2300...(1)

50X+40Y=21000...(2)

Solving the system of equations:

10X+3Y=2300...(1)

10X=2300-3Y

X=(2300-3Y)/10

Substituting X in (2) we have:

50X+40Y=21000

50[(2300-3Y)/10]+40Y=21000

50[(2300/10)-(3Y/10)]+40Y=21000

50[230-(3Y/10)+40Y=21000

11500-(150Y/10)+40Y=21000

11500-15Y+40Y=21000

11500+25Y=21000

25Y=21000-11500

25Y=9500

Y=380

Substituting Y in (1) we have:

10X+3Y=2300...(1)

10X+3(380)=2300

10X+1140=2300

10X=2300-1140

10X=1160

X=116

So 116 units of the first product and 380 units of the second product can be transported in a single shipment with one truck.

8 0
2 years ago
A garden measuring 16 meters by 8 meters is going to have a walkway constructed all around the perimeter, increasing the total a
Semenov [28]

Answer:

The width of the pathway is:

  • <u>7 meters</u>.

Step-by-step explanation:

To identify the width of the pathway, you must remember the area formula of a rectangle:

  • Area of a rectangle = length * width.

From which the width can be cleared:

  • Width of a rectangle = area / length.

We know that the length of the terrain was not modified since the pathway is in the perimeter of the rectangle (16 m) and that the new area is 240 m^2, so we only have to replace the cleared formula:

  • Width of a rectangle = 240 m^2 / 16 m = 15 m.

The new width is equal to 15 meters, but since the question is not the total width but the width of the pathway, the width of the previously provided land must be subtracted from the value obtained.

  • <u>Pathway width = Total width - Garden width. </u>
  • <u>Pathway width = 15m - 8m = 7 meters.</u>
7 0
2 years ago
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