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11Alexandr11 [23.1K]
1 year ago
8

A football filters that is 60 m wide and 110 m long is being paved over to make a parking lot. The builder ordered 660,000,000 c

m3 of cement. How thick must the cement be to cover the field using 660,000,000 cm3 of cement?
Mathematics
1 answer:
ad-work [718]1 year ago
4 0
The answer is 10 cm

Imagine cement cover as a rectangle which volume is 660,000,000 cm3. So this rectangle has width (w = 60m), length (l = 110m), and height (h = ?). The height of the rectangle is actually a thickness of the cement layer. So, we will use the formula for the volume (V) of the rectangle to calculate the thickness:
V = w · l · h

It is given:
V = 660,000,000 cm³
w = 60 m = 60 · 100 cm = 6,000 cm
l = 110 m = 110 · 100 cm = 11,000 cm
h = ?

Using the formula: V = w · l · h
660,000,000 = 6,000 · 11,000 · h
660,000,000 = 66,000,000 · h
⇒ h = 660,000,000 ÷ 66,000,000 = 10 cm
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Using the side-splitter theorem, which segment length would complete the proportion?
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Learning Task 3. Find the equation of the line. Do it in your notebook.
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Answer:

1) The equation of the line in slope-intercept form is y = 5\cdot x +9. The equation of the line in standard form is -5\cdot x + y = 9.

2) The equation of the line in slope-intercept form is y = \frac{2}{5}\cdot x +\frac{14}{5}. The equation of the line in standard form is -2\cdot x +5\cdot y = 14.

3) The equation of the line in slope-intercept form is y = 3\cdot x +4. The equation of the line in standard form is -3\cdot x +y = 4.

4) The equation of the line in slope-intercept form is y = 2\cdot x + 6. The equation of the line in standard form is -2\cdot x +y = 6.

5) The equation of the line in slope-intercept form is y = \frac{5}{6}\cdot x -\frac{7}{6}. The equation of the line in standard from is -5\cdot x + 6\cdot y = -7.

Step-by-step explanation:

1) We begin with the slope-intercept form and substitute all known values and calculate the y-intercept: (m = 5, x = -1, y = 4)

4 = (5)\cdot (-1)+b

4 = -5 +b

b = 9

The equation of the line in slope-intercept form is y = 5\cdot x +9.

Then, we obtain the standard form by algebraic handling:

-5\cdot x + y = 9

The equation of the line in standard form is -5\cdot x + y = 9.

2) We begin with a system of linear equations based on the slope-intercept form: (x_{1} = 3, y_{1} = 4, x_{2} = -2, y_{2} = 2)

3\cdot m + b = 4 (Eq. 1)

-2\cdot m + b = 2 (Eq. 2)

From (Eq. 1), we find that:

b = 4-3\cdot m

And by substituting on (Eq. 2), we conclude that slope of the equation of the line is:

-2\cdot m +4-3\cdot m = 2

-5\cdot m = -2

m = \frac{2}{5}

And from (Eq. 1) we find that the y-Intercept is:

b=4-3\cdot \left(\frac{2}{5} \right)

b = 4-\frac{6}{5}

b = \frac{14}{5}

The equation of the line in slope-intercept form is y = \frac{2}{5}\cdot x +\frac{14}{5}.

Then, we obtain the standard form by algebraic handling:

-\frac{2}{5}\cdot x +y = \frac{14}{5}

-2\cdot x +5\cdot y = 14

The equation of the line in standard form is -2\cdot x +5\cdot y = 14.

3) By using the slope-intercept form, we obtain the equation of the line by direct substitution: (m = 3, b = 4)

y = 3\cdot x +4

The equation of the line in slope-intercept form is y = 3\cdot x +4.

Then, we obtain the standard form by algebraic handling:

-3\cdot x +y = 4

The equation of the line in standard form is -3\cdot x +y = 4.

4) We begin with a system of linear equations based on the slope-intercept form: (x_{1} = -3, y_{1} = 0, x_{2} = 0, y_{2} = 6)

-3\cdot m + b = 0 (Eq. 3)

b = 6 (Eq. 4)

By applying (Eq. 4) on (Eq. 3), we find that the slope of the equation of the line is:

-3\cdot m+6 = 0

3\cdot m = 6

m = 2

The equation of the line in slope-intercept form is y = 2\cdot x + 6.

Then, we obtain the standard form by algebraic handling:

-2\cdot x +y = 6

The equation of the line in standard form is -2\cdot x +y = 6.

5) We begin with a system of linear equations based on the slope-intercept form: (x_{1} = -1, y_{1} = -2, x_{2} = 5, y_{2} = 3)

-m+b = -2 (Eq. 5)

5\cdot m +b = 3 (Eq. 6)

From (Eq. 5), we find that:

b = -2+m

And by substituting on (Eq. 6), we conclude that slope of the equation of the line is:

5\cdot m -2+m = 3

6\cdot m = 5

m = \frac{5}{6}

And from (Eq. 5) we find that the y-Intercept is:

b = -2+\frac{5}{6}

b = -\frac{7}{6}

The equation of the line in slope-intercept form is y = \frac{5}{6}\cdot x -\frac{7}{6}.

Then, we obtain the standard form by algebraic handling:

-\frac{5}{6}\cdot x +y =-\frac{7}{6}

-5\cdot x + 6\cdot y = -7

The equation of the line in standard from is -5\cdot x + 6\cdot y = -7.

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