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zaharov [31]
2 years ago
5

A box can hold a maximum of 8 cans. You have 50 cans to put in boxes. What is the smallest number of boxes you need to store all

of the cans in boxes?
Mathematics
1 answer:
xeze [42]2 years ago
3 0

Answer:

7boxes

Step-by-step explanation:

A box can hold a maximum of 8 cans

You have a total of 50 cans

The problem here is to determine the minimum number of boxes that can hold the 50 cans

Let the minimum number of boxes = y

The minimum required will be such that:

The Product of The number of cans X Number of Required boxes ≥50

8y≥50

y≥50/8

y≥6.25

Since a box have a fractional value, the minimum number of boxes required to store 50 cans will be the nearest whole number which in this case is 7.

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Answer:

21 savae just relased an album

Step-by-step explanation:

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2 years ago
Louden County Wildlife Conservancy counts butterflies each year. Data over the last three years regarding four types of butterfl
MrRa [10]

Incomple question. However, here's the remaining part of the question:

14

2009

Meadow Fritillary= 5

Variegated Fritillary= 7

Zebra Swallowtail= 33

Eastern-Tailed Blue= 242

Louden County Butterfly Count

2010

Meadow Fritillary 34

Variegated Fritillary 95

Zebra Swallowtail 21

Eastern-Tailed Blue 168

2011

Meadow Fritillary

Variegated Fritillary

Zebra Swallowtail

Eastern-Tailed Blue

10

170

<u>Options</u>:

A) All butterfly populations are steadily decreasing.

B)All butterfly populations were larger than usual in 2010.

C)The Eastern-Tailed Blue butterfly is more common than the others.

D)The Meadow Fritillary is equally common as the Variegated Fritillary

Answer:

<u>C</u>

Step-by-step explanation:

Looking through the above count data by Louden County Wildlife Conservancy from 2009 to 2011 we notice the Eastern- Trailed Blue butterfly has a higher count, which implies that the Eastern-Tailed Blue butterfly is more common than the other butterflies.

Therefore, we could infer from the samples, that the Eastern-Tailed Blue butterfly is more common than others from the records of the past 3 three years.

5 0
2 years ago
A bucket that has a mass of 30 kg when filled with sand needs to be lifted to the top of a 30 meter tall building. You have a ro
Rom4ik [11]

Answer:

765 J

Step-by-step explanation:

We are given;

Mass of bucket = 30 kg

Mass of rope = 0.3 kg/m

height of building= 30 meter

Now,

work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand

Or W = W1 + W2

Work done in lifting the rope is given as,

W1 = Force x displacement

W1 = (30,0)∫(0.2x .dx)

Integrating, we have;

W1 = [0.2x²/2] at boundary of 30 and 0

W1 = 0.1(30²)

W1 = 90 J

work done in lifting the sand is given as;

W2 = (30,0)∫(F .dx)

F = mx + c

Where, c = 30 - 15 = 15

m = (30 - 15)/(30 - 0)

m = 15/30 = 0.5

So,

F = 0.5x + 15

Thus,

W2 = (30,0)∫(0.5x + 15 .dx)

Integrating, we have;

W2 = (0.5x²/2) + 15x at boundary of 30 and 0

So,

W2 = (0.5 × 30²)/2) + 15(30)

W2 = 225 + 450

W2 = 675 J

Therefore,

work done lifting the bucket (sand and rope) to the top of the building,

W = 90 + 675

W = 765 J

5 0
2 years ago
Stacey owns a lot that has 180 feet of front footage and contains 36,000 square feet. She purchases two lots adjacent to each si
bija089 [108]
The graph of the function f(x)=(x+2)(x+6) is shown

The statement the function is negative for all real values of x where x <-2
3 0
2 years ago
Read 2 more answers
Bob is having a party and want to order some cake. there will be 57 guest and he wants to make sure that everyone gets a slice o
Dafna1 [17]
To find out which cake is better for the price, we need to multiply the cake amounts by how many cakes of that kind we need. You need 5 20cm cakes, so we multiply 5 by the price of the 20cm cake (13.50) to get $67.50. You need 3 25cm cakes, so 3 x 18.75 = 56.25.

20cm cake: $67.50
25cm cake: $56.25

Answer: The 25cm cake is cheaper for more people.
4 0
2 years ago
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