What are the partial products to 652 x 4 =2608
2 answers:
Answer:
Partial product is a method of multiplication of two numbers after writing them in columns,
Here, the given problem,
652 x 4
Steps of partial product are as follow,
Step 1 : Write the numbers under each other ( shown in diagram )
Step 2 : First multiply 4 and 2, write it in first row,
Step 3 : Then multiply 4 and 20, write it in second row,
Step 4 : Again multiply 4 and 600, write it in third row,
Step 5 : finally, add them
We get,
652 x 4 = 2608
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The figure shown below illustrates the problem.
The volume of the empty cone is
V₁ = (1/3) π r²h
The volume of the sphere is
V₂ = (4/3) π r³
Because the melted ice cream completely fills the cone, therefore
V₁ = V₂
(1/3) π r² h = (4/3) π r³
Divide each side by (1/3) π r².
h = 4r
Answer:
The height of the cone is 4 times greater than the radius f the cone.
The volume of the empty cone is
V₁ = (1/3) π r²h
The volume of the sphere is
V₂ = (4/3) π r³
Because the melted ice cream completely fills the cone, therefore
V₁ = V₂
(1/3) π r² h = (4/3) π r³
Divide each side by (1/3) π r².
h = 4r
Answer:
The height of the cone is 4 times greater than the radius f the cone.
Answer:
- Fantasy: 3 barrels
- Ecstasy: 1 barrel
Step-by-step explanation:
<u>Given</u>
Fantasy uses 4 lb of nuts, 3 lb of chocolate, for a profit of $50
Ecstasy uses 4 lb of nuts, 1 lb of chocolate, for a profit of $40
In stock are 16 lb of nuts, 10 lb of chocolate
<u>Find</u>
amount of each to maximize profit
<u>Solution</u>
Let x and y represent barrels of Fantasy and Ecstasy, respectively. Then the limitations on production are ...
4x +4y ≤ 16 . . . lb of nuts
3x +y ≤ 10 . . . . lb of chocolate
We want to maximize
50x +40y
The graph shows the feasible region. Its vertices are ...
(0, 4), (3, 1), (3.33, 0)
Profit is maximized at $190 when production is 3 barrels of Fantasy and 1 barrel of Ecstasy.
Answer:
Therefore the value of k = 6.
Step-by-step explanation:
Given:
LN = m
NM = l
OM = k
NO = 4
LO = 8
LM = 8 + k and
Δ LNM ,Δ LON and Δ MON are right Triangle.
To Find :
Om = k = ?
Solution:
In Right angle Triangle By Pythagoras Theorem we have,
So, In Right angle Triangle Δ LON we have,
LN² = ON² + OL²
m² = 4² + 8²
m² = 80 ............( 1 )
Now in Right angle Triangle Δ MON we have,
MN² = ON² + MO²
l² = 4² + k² ....................( 2 )
Now In Right angle Triangle Δ LNM we have,
LM² = LN² + MN²
(8 + k)² = m² + l² .................( 3 )
Substituting equation 1 and equation 2 in equation 3
(8+k)² = 80 + 4² + k²
Applying (A+B)² = A² +2AB + B² we get
Therefore the value of k = 6.
