A fabric store sells two types of ribbon. One customer buys 3 rolls of the lace ribbon and 2 rolls of the satin ribbon and has a
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AB is divided into 8 equal parts and point C is 1 part FROM A TO B, so the ratio is 1:7, with C being 1/7 of the way. The ratio is k, found by writing the numerator of the ratio (1) over the sum of the numerator and denominator (1+7). So our k value is 1/8. Now we need to find the rise and the run (slope) of the points A and B. 
. That gives us a rise of -4 and a run of 12. The coordinates of C are found in this formula: ![C(x,y)=[ x_{1} +k(run), y_{1} +k(rise)]](https://tex.z-dn.net/?f=C%28x%2Cy%29%3D%5B%20x_%7B1%7D%20%2Bk%28run%29%2C%20y_%7B1%7D%20%2Bk%28rise%29%5D)
. Filling in accordingly, we have ![C(x,y)=[-3+ \frac{1}{8}(12),9+ \frac{1}{8}(-4)]](https://tex.z-dn.net/?f=C%28x%2Cy%29%3D%5B-3%2B%20%5Cfrac%7B1%7D%7B8%7D%2812%29%2C9%2B%20%5Cfrac%7B1%7D%7B8%7D%28-4%29%5D%20%20)
which simplifies a bit to 
. Finding common denominators and doing the math gives us that the coordinates of point C are 
. There you go!
Answer: The greatest number of plates Lenin can prepare = 4
and there will be 3 chickens and 4 rolls in each plate.
Step-by-step explanation:
Given: Lenin is preparing dinner plates. He has 12 pieces of chicken and 16 rolls.
To make all the plates identical without any food left over, the greatest number of plates Lenin can prepare = G.C.D.(12,16)=4
The number of pieces of chicken in each plate =
The number of pieces of rolls in each plate =
So, the greatest number of plates Lenin can prepare = 4
and there will be 3 chickens and 4 rolls in each plate.