Whatever% of anything is just (whatever/100) * anything.
so 56% of 75 mates like it, how much is 56% of 75? well is just (56/100) * 75, namely 42.
and 80% of 60 relatives like it as well, how much is 80% of 60? well, is just (80/100) * 60, namely 48.
how many more? well, 48 - 42.
Part 1)
we have
the scale is 
the distance on a map is 
we know that
The scale is equal to the distance on a map divided by the real distance
Let
x------> distance on a map
y-------> real distance
S-------> scale
In this part we have
Find the value of y
Substitute the values
Convert to kilometers
Part 2)
In this part we have
Find the value of x
Substitute the values
Convert to centimeters
therefore
the answer is
The distance is 
First, create a scale that includes all the numbers- that being, you can plot both the minimum and maximum values on it.
Next, draw a line of a set height (I tend to use 2 squares in my work) where the median is. Next, draw similar lines, at the same height, for the rest of the values- both quartiles and the maximum values. You can obviously do this in whatever order you like, but that's how I do it.
Next, join up the tops and bottoms of the quartiles, with the median in the middle, and connect the middles of the quartiles to their corresponding minimum or maximum values.
Voila, my friend. You have a box plot.
Solving an equation means finding the value of x which will make the equation true.
We need to undo whatever is done to x to get it by itself.
Conclusion:
Since we end up with an equation which is not TRUE, there is NO solution for this equation. If we graph both the equations, they will end up as a parallel lines which will never meet.
Given that Roger is building a storage shed with wood blocks that are in the shape of cubic prisms.
cube is basicallye a box which is made of squares. That is all the sides (lenght, width and height) are equal.
Now we have to determine, Can he build a shed that is twice as high as it is wide.
that means if width is 1 then height should be twice which is 2.
yes that is possible if we put one cubical prism over another cubical prism. then height of shed due to two prism will be twice than the width.
Hence correct choice should be "A. Yes. For every block of width, he could build two blocks high."
