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2 years ago

9

Eliza likes to make daily events into games of chance. For instance, before she went to buy ice cream at the local ice cream par

lor, she created two spinners. The first has her three favorite flavors while the second has “Cone” and “Dish.”
Eliza will order whatever comes up on the spinners.

What is the probability that she will be eating tutti fruitti ice cream from a dish?

1 answer:

sergejj [24]2 years ago

6 0

Answer:

1/6

Step-by-step explanation:

two events need to happen: tutti frutti needs to be shown by first spinner and second spinner needs to show dish

probability of tutti frutti = 1/3

probability of dish = 1/2

probability of both events = 1/3 * 1 /2 = 1/6

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This is an incomplete question, here is a complete question.

A hurricane wind blows across a 7.00 m × 12.0 m flat roof at a speed of 150 km/h.

What is the pressure difference Δp = p(inside)-p(outside)? Use 1.28 kg/m³ for the density of air. Treat the air as an ideal fluid obeying Bernoulli's equation.

Answer : The pressure difference will be, $1.11\times 10^3Pa$

Step-by-step explanation :

As we are given:

Speed = 150 km/h = 41.66 m/s

Density = $\rho=1.28kg/m^3$

Area = A = 7.00 m × 12.0 m

Formula used :

$\Delta P=\frac{1}{2}\times \rho \times v^2$

Now put all the given values in this formula, we get:

$\Delta P=\frac{1}{2}\times (1.28kg/m^3)\times (41.66m/s)^2$

$\Delta P=1.11\times 10^3Pa$

Thus, the pressure difference will be, $1.11\times 10^3Pa$

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2 years ago

A new curing process developed for a certain type of cement results in a mean compressive strength of 5000 kilograms per square

Sedbober [7]

Answer:

$\alpha =0.0668$

Step-by-step explanation:

Data given and notation

The info given by the problem is:

$n=25$ the random sample taken

$\mu =5000$ represent the population mean

$\sigma =100$ represent the population standard deviation

The critical region on this case is $\bar X$ so then if the value of $\bar X \geq 4970$ we fail to reject the null hypothesis. In other case we reject the null hypothesis

Null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the true mean is 5000, the system of hypothesis would be:

Null hypothesis: $\mu = 5000$

Alternative hypothesis: $\mu \neq 5000$

Let's define the random variable X ="The compressive strength".

We know from the Central Limit Theorem that the distribution for the sample mean is given by:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

Find the probability of committing a type I error when H0 is true.

The definition for type of error I is reject the null hypothesis when actually is true, and is defined as $\alpha$ the significance level.

So we can define $\alpha$ like this:

$\alpha= P(Error I)= P(\bar X$

And in order to find this probability we can use the Z score given by this formula:

$Z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And the value for the probability of error I is givn by:

$\alpha= P(\bar X$

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This chart shows what happens when each object is placed on a balance with a 10 kg weight on the other side.

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Answer:

Object 1 is the heaviest object.

Step-by-step explanation:

The first column of the table tells you ...

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Answer:

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Answer:

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Step-by-step explanation:

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General formula of permutations of n objects taken r at time is:

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The general formula of combinations of n objects taken r at a time is:

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2 years ago

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