Question

Suppose the equation for line A is given by 12x=9y+27. If line A and B are perpendicular and the point (16,-12) lies on line B, then write the equation for line B

Answer 1

Answer:

$y=-\frac{3}{4} x-8$

Step-by-step explanation:

he equation for line A is given by 12x=9y+27

Equation of line is y=mx+b where m is the slope

$12x=9y+27$

Subtract 27 on both sides

$12x-27=9y$

Divide both sides by 9

$y=\frac{4}{3} x-3$

Slope of the given line is 4/3

Slope of perpendicular lines are negative reciprocal of one another

slope of perpendicular line is -3/4

$m=-3/4, (16,-12)$

$y-y1=m(x-x1)$

$y+12=\frac{-3}{4}(x-16)$

Multiply fraction inside the parenthesis

$y+12=-\frac{3}{4} x+4$

Now subtract 12 from both sides

$y=-\frac{3}{4} x-8$

Answer 2

Answer:

The answer is -3/4x

Step-by-step explanation:

I just did it and I got it right .