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Gekata [30.6K]
2 years ago
8

A recent study reported that high school students spend an average of 94 minutes per day texting. Jenna claims that the average

for the students at her large high school is greater than 94 minutes. She will conduct a study to investigate this claim.
(b) Based on a sample of 32 students, Jenna calculated a sample mean of 96.5 minutes and a sample standard deviation of 6.3 minutes. Assume all conditions for inference are met. At the significance level of α=0.05, do the data provide convincing statistical evidence to support Jenna’s claim? Complete an appropriate inference procedure to support your answer.
Mathematics
1 answer:
larisa [96]2 years ago
3 0

Answer:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

Step-by-step explanation:

Jenna claims that the average time of texting at her larger high school is greater than 94 minutes per day.

From here we can see that we have to perform a hypothesis test about a sample mean. The null and alternate hypothesis will be:

Null Hypothesis: \mu \leq  94

Alternate Hypothesis: \mu > 94

Jenna collected data from a sample of 32 students. So, sample size will be:

Sample Size = n = 32

Sample Mean = x = 96.5

Sample Standard Deviation = s = 6.3

We have to perform a hypothesis test, to test Jenna's claim. Since, the value of Population Standard Deviation is unknown and the value of Sample Standard Deviation is known, we will use One Sample t-test in this case.

The formula to calculate the test statistic is:

t=\frac{x-\mu}{\frac{s}{\sqrt{n}}}

Using the values, we get:

t=\frac{96.5-94}{\frac{6.3}{\sqrt{32} } }=2.245

The degrees of freedom will be:

df = n - 1 = 32 - 1 = 31

We have to convert the t-score 2.245 with 31 degrees of freedom to its equivalent p-value. From t-table this value comes out to be:

p-value = 0.0160

The significance level is:

\alpha =0.05

Since, the p-value is lesser than the level of significance, we reject the Null Hypothesis.

Conclusion:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

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Answer:

Step-by-step explanation:

A

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Fill in the blanks. a. A​ relative-frequency distribution is to a variable as a​ __________ distribution is to a random variable
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Answer:

a. A​ relative-frequency distribution is to a variable as a​ ___probability_______ distribution is to a random variable. b. A​ relative-frequency histogram is to a variable as a​ _____probability_____ histogram is to a random variable.

Step-by-step explanation:

Probability is a type of mathematics which deals with numerical descriptions of how likely an event would occur, or how likely it is that a the occurrence would be true. The probability of an event is usually between 0 and 1,

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4 0
2 years ago
The graph represents the function where electricity usage in kilowatts per hour of a clock radio varies directly with the number
geniusboy [140]

Answer:

Reasonable estimation for constant of variation is 0.25 kWh per day.    

Step-by-step explanation:

We are given the following information in the question:

  • The graph represents the function where electricity usage.
  • Electricity usage in kilowatts per hour of a clock radio varies directly with the number of days.
  • The x-axis shows the number of days and usage in kilo-watt per hour is showed on the y-axis.
  • Some coordinates of the graph are: (0,0), (2,0.5) and (6,1.5)

Formula for constant of variation:

\displaystyle\frac{y_2-y_1}{x_2-x_1}

Putting the values from the coordinates (2,0.5) and (6,1.5), we get:

\displaystyle\frac{1.5-0.5}{6-2} = \frac{1}{4} = 0.25\text{ kilowatt-hours per day}

Hence, reasonable estimation for constant of variation is 0.25 kWh per day.

7 0
2 years ago
Read 2 more answers
Diana drove at an average speed of 50 miles an hour for 1.5 hours.she then drove at an average speed of 42 miles an hour for 2.2
weqwewe [10]

Diana drove 169.5 miles in total.

Step-by-step explanation:

Average speed first = 50 miles

Driving time = 1.5 hours

Distance = Speed*Time

Distance=50*1.5\\Distance=75\ miles

Average speed afterwards = 42 miles

Driving time = 2.25 hours

Distance=Speed*Time

Distance=42*2.25\\Distance=94.5\ miles

Total distance = 75+94.5

Total distance = 169.5 miles

Diana drove 169.5 miles in total.

Keywords: distance, speed

Learn more about speed at:

  • brainly.com/question/7294502
  • brainly.com/question/7490805

#LearnwithBrainly

4 0
2 years ago
7. If SK = 13x - 5, KY= 2x + 9, and SY = 36-x, find each value.
sweet [91]

Answer:

SY=34, SK=21 and KY=13

Step-by-step explanation:

we have that

SY=SK+KY

substitute the given values

(36-x)=(13x-5)+(2x+9)

solve for x

36-x=15x+4

15x+x=36-4

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x=2

<em>Find the value of SY</em>

SY=(36-x)=36-2=34

<em>Find the value of SK</em>

SK=(13x-5)=13(2)-5=21

<em>Find the value of KY</em>

KY=(2x+9)=2(2)+9=13

5 0
2 years ago
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