Ask question

Ask question

All categories

2 years ago

14

Use the result from part c to find the two solutions to the equation 2x2−3x−5=0. enter the two solutions separated by a comma. (

the order is not important.)

1 answer:

-BARSIC- [3]2 years ago

5 0

<span>The equation 2x^2-3x-5=0 a=2, b=-3, c=-5 To find x = -b Â± âšb2 - 4ac 2a x=(3 + 7) /4 and (3-7) /4 x = 10/4 = 5/2 and -4/4 x = 2.5 , 1</span>

You might be interested in

Let e1= 1 0 and e2= 0 1 , y1= 4 5 , and y2= −2 7 , and let T: ℝ2→ℝ2 be a linear transformation that maps e1 into y1 and maps

Furkat [3]

Answer:

The image of $\left[\begin{array}{c}4&-4\end{array}\right]$ through T is $\left[\begin{array}{c}24&-8\end{array}\right]$

Step-by-step explanation:

We know that $T:$ $IR^{2}$ → $IR^{2}$ is a linear transformation that maps $e_{1}$ into $y_{1}$ ⇒

$T(e_{1})=y_{1}$

And also maps $e_{2}$ into $y_{2}$ ⇒

$T(e_{2})=y_{2}$

We need to find the image of the vector $\left[\begin{array}{c}4&-4\end{array}\right]$

We know that exists a matrix A from $IR^{2x2}$ (because of how T was defined) such that :

$T(x)=Ax$ for all x ∈ $IR^{2}$

We can find the matrix A by applying T to a base of the domain ( $IR^{2}$ ).

Notice that we have that data :

$B_{IR^{2}}=$ { $e_{1},e_{2}$ }

Being $B_{IR^{2}}$ the cannonic base of $IR^{2}$

The following step is to put the images from the vectors of the base into the columns of the new matrix A :

$T(\left[\begin{array}{c}1&0\end{array}\right])=\left[\begin{array}{c}4&5\end{array}\right]$ (Data of the problem)

$T(\left[\begin{array}{c}0&1\end{array}\right])=\left[\begin{array}{c}-2&7\end{array}\right]$ (Data of the problem)

Writing the matrix A :

$A=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]$

Now with the matrix A we can find the image of $\left[\begin{array}{c}4&-4\\\end{array}\right]$ such as :

$T(x)=Ax$ ⇒

$T(\left[\begin{array}{c}4&-4\end{array}\right])=\left[\begin{array}{cc}4&-2\\5&7\\\end{array}\right]\left[\begin{array}{c}4&-4\end{array}\right]=\left[\begin{array}{c}24&-8\end{array}\right]$

We found out that the image of $\left[\begin{array}{c}4&-4\end{array}\right]$ through T is the vector $\left[\begin{array}{c}24&-8\end{array}\right]$

3 0

2 years ago

Brittany surveyed the students in three different Chemistry classes regarding the average number of hours of sleep they get each

aalyn [17]

Class B has the most consistant sleep because there is less of a difference between 6.87 and 3.65 than the other classes.

6 0

2 years ago

Read 2 more answers

Xy+(4(20))>x-5y(2+9-7)

prohojiy [21]

I'll solve for y xy+(4(20))>x-5y(2+9-7)

xy+4(20)>x-5y(2+9-7)

xy+4(20)>x-5y(4)

xy+4(20)>x-20y

xy+80>x-20y

xy+20y+80>x

y(x+20)>-80+x

y>(-80+x)/(x+20)

3 0

2 years ago

Alliance Cannery has two assembly lines. One produces 24 cans of fruit per minute; the other produces 64 cans of vegetables per

sergey [27]

Let
x----------------------- > number of <span>cans of fruit-----------------> 24 per minute
</span>y----------------------- > number of cans of vegetables-------> 64 per minute
<span>z----------------------- > number of cans of food per minute
t----------------------- > time in minutes

z=(x+y)*t
z=(24+64)*t--------------- > 88t
z=88t---------------------------------- > this is the equation required
we know that z=384
then
</span>384=88t------------- > t=4.36 minutes

5 0

2 years ago

Read 2 more answers

. Over the next two days, Clinton Employment Agency is interviewing clients who wish to find jobs. On the first day, the agency

Vedmedyk [2.9K]

Answer:

4

Step-by-step explanation:

Given that :

Clients are interviewed in groups of 2 on the first day; meaning two persons at a time

Second day, clients are interviewed in groups of 4; meaning 4 persons at a time.

Therefore, if the same number of clients are to be interviewed on each day, the smallest number of clients that could be interviewed each day could be obtained by getting the Least Common Multiple of both numbers: 2 and 4

- - - - 2 - - - 4

2 - - - 1 - - - 2

2 - - - 1 - - - 1

Therefore, the Least common multiple is (2 * 2) = 4

Therefore, the smallest number of clients that could be interviewed each day is 4.

5 0

2 years ago