Answer:
Compatible width of rectangular banquet hall could be 90 feet approximately.
Step-by-step explanation:
Given
Area of a rectangular banquet hall = 7400 square feet
Length of rectangular banquet hall = 82 feet
We need to calculate width of the rectangular banquet hall.
Now Area of rectangle is equal to length times width.
Framing in equation form we get;
Substituting the given values we get;
Now by definition of Compatible numbers which state that:
"Compatible numbers are the numbers that are easy to add, subtract, multiply, or divide mentally. Compatible numbers are close in value to the actual numbers that make estimating the answer and computing problems easier."
Now By Using width as 90 feet and length as 82 feet we get area as 7380 sq ft. which is closet to actual area which is 7400 sq ft.
Hence we can say compatible width could be 90 feet approximately.
we know that
<u>1) If the line segment AB is parallel to the line segment DC</u>
then
m∠1=m∠D -------> by corresponding angles
<u>2) If the line segment AD is parallel to the line segment BC</u>
then
m∠3=m∠B -------> by corresponding angles
Answer:
Im not too sure given yopur formatting, but I believe you meant this: -((3/8)/(-1/4))
therfore, the answer is: 3/2
Step-by-step explanation:
You can seperate the two fractions as 3/8 divided by -1/4, which is equal to 3/8 * 4/-1, simply multiply across to get 12/-8, which simplifies to -3/2. Flip the sign to get 3/2
Answer:
79.2 tons
Step-by-step explanation:
What must be done is to apply a proportion rule, taking into account what happened in the registry and what is wanted for this new year. In the following way we can calculate the amount of tons of oranges.
Powder concentrate Oranges
45 tons -------------------------> 54 Tons
66 tons -------------------------> X Tons
X = 66 * 54/45
X = 79.2, that is to say that 79.2 tons are necessary to produce 66 tons of powder concentrate to make juice.
The last one is the only one that makes sense according to the standard position function. -16t^2 is the pull of gravity on an object in free fall, and the height is 120 feet above the ground. Hopefully that's what you need since there's no graph we can refer to
