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timofeeve [1]
2 years ago
5

E varies directly with the square root of C. If E=40 when C=25, find: C when E = 10.4

Mathematics
2 answers:
sukhopar [10]2 years ago
6 0

Answer: C = 1.69

Step-by-step explanation:

E is proportional to √C

To remove proportionality, introduce a constant (k).

E = k × √C

From question,

E = 40 and C = 25

So,

40 = k ×√25

40 = k × 5

k = 8

Now,

C = ?

E = 10.4

k = 8

E = k × √C

10.4 = 8 × √C

10.4 / 8 = √C

( 10.4 / 8 ) ^ 2 = C

C = 1.69

Ilia_Sergeevich [38]2 years ago
4 0

Answer:

Step-by-step explanation:

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Answer:

The mean number of successful surgeries is 1.57.

The variance of the number of successful surgeries is 0.3111.

Step-by-step explanation:

STEP 1

If the tear on the left knee has a rim width of less than 3mm, the probability that the surgery on the left knee will be successful (ls) is 0.90.

That isP(Is)=0.90

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The probability that the surgery on the left knee will fail (lf) is 0.10. That isP(V)=0.10

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If the tear on the right knee has a rim width of 3-6 mm, the probability that the surgery on the right knee will be successful (rs) is 0.67. That isP(rs)=0.67

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The probability that the surgery on the right knee will fail (rf) is 0.33.

That isP(vf)= 0.33

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Let the random variable X denote the number of successful surgeries. The range of X is{0,1,2)

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Now find the probabilities associated with the possible values of X. The number of successful surgeries is equal to 0 if the surgeries on both knees fail. Since the surgeries are independent, we have:

P(X = 0)=P(lf and rf)

= P()P(rf)

=(0.10)(0.33)

= 0.033

The number of successful surgeries is equal to 1 if the surgery on one knee is successful and the surgery on the other knee fails, that is

P(X =1)= P((ls and rf) or (if and rs))

= P(Is)P(rf)+P(V)P(rs)

= (0.90)(0.33)+(0.10)(0.67)

= 0.364

The number of successful surgeries is equal to 2 if the surgeries on both knees are successful, that is

P(X = 2)=P(ls and rs)

= P(Is) P(rs)

=(0.90)(0.67)

= 0.603

So, the probability mass function of X is the following

X        0              1               2

f(x)     0.033      0.364      0.603

The mean number of successful surgeries is,

E(X)=∑xP(x)

=(0×0.033) +(1×0.364)+(2×0.603)

=1.57

the mean number of successful surgeries is 1.57

The expected value is obtained by taking the summation of the product of each possible value of the random variable X with its corresponding probabilities. Thus, the mean number of successful surgeries is 1.57.

STEP 2

The variance of the number of successful surgeries is,

Var(X)=∑x²P(x)-(E(x²)

=(0×0.033) + (1 × 0.364) +(2 × 0.603) - (1.57)²

= 2.776 -(1.57)²

=0.3111

The variance of the number of successful surgeries is 0.3111.

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