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My name is Ann [436]
2 years ago
14

The cost of soup, s, varies directly with the number of cans, c. When c is 4, the cost is 3$. Which graph represents the cost of

soup?

Mathematics
2 answers:
sweet [91]2 years ago
6 0
S=3/4c since when c=4, s must equal 3
kobusy [5.1K]2 years ago
3 0

Answer:

Here,

s represents the cost of soup and c represents the number of can,

Also, s varies directly with c,

⇒ s ∝ c

⇒ s = kc -----(1)

Where, k is the proportionality constant,

Given, when c = 4, s = 3,

From equation (1),

3=k(4)

\implies k=\frac{3}{4}

Again from equation (1),

s=\frac{3}{4}c

Let x-axis represents the number of can and y-axis represents the cost of soup,

For graphing :

s=\frac{3}{4}c is a straight line

Where, s ≥ 0 and c ≥ 0 ( cost and number of cans can not be negative )

When, c = 0, s = 0,

When c = 4, s=\frac{3}{4}\times 4=3

When c = 8, s=\frac{3}{4}\times 8=6

When c = 16, s=\frac{3}{4}\times 16=12

Thus, the line s=\frac{3}{4}c  is passing from the points (0,0), (4,3), (8,6) and (16,12).

You might be interested in
How many ounces of pure nickel must be added to 150 ounces of alloy 70% pure to make an alloy which is 85% pure?
galben [10]

Answer:

150 oz.

Step-by-step explanation:

There are already 150 ounces of alloy of nickel.

Of this 150 oz, 70% is pure i.e. nickel content = 150(0.7) = 105 oz

Now available is

Nickel       Other metals

105                  45

Let x oz of pure nickel is added.

Then new alloy will have 105+x oz nickel in total of 150+x oz.

Percentage pure = \frac{105+x}{150+x} =85%

Simplify to get

\frac{105+x}{150+x} =\frac{85}{100} \\\\Cross multiply:\\85(150+x) =100(105+x)\\12750+85x =10500+100x\\100x-85x = 12750-10500\\15x = 2250\\x = 150

Hence answer is 150 oz should be added.

6 0
1 year ago
Points b,d, and f are midpoints of the sides of triangle ACE. EC=30 and DF= 17 find AC
Margaret [11]

Answer:

Your answer should be AC=2DF=34

Step-by-step explanation:


5 0
1 year ago
Arthur borrowed $2,100 from the bank. 3 years later, Arthur owes the bank $2,478. What was the percentage rate of simple interes
ASHA 777 [7]

Answer:

Percentage Rate=6%

Step-by-step explanation:

Total borrowed=$2,100

Time=3 years

Rate=?

Total amount owed after 3 years= total borrowed + simple interest

$2,478=$2,100 + x

X=$2,478 - $2,100

=$378

The simple interest=$378

Simple interest=P×R×T

Where,

P= principal=$2,100

R=Rate=?

T=Time=3 years

Simple interest=$378

Simple interest=P×R×T/100

$378=$2,100×R×3/100

$378=$6,300R/100

$378=$63R

R=$378/$63

R=6

Therefore,

Rate=6%

7 0
2 years ago
Read 2 more answers
A random sample of 15 observations from the first population revealed a sample mean of 350 and a sample standard deviation of 12
marissa [1.9K]

Answer:

Step-by-step explanation:

Hello!

You have two random samples obtained from two different normal populations.

Sample 1

n₁= 15

X[bar]₁= 350

S₁= 12

Sample 2

n₂= 17

X[bar]₂= 342

S₂= 15

At α: 0.05 you need to obtain the p-value for testing variances for a one tailed test.

If the statistic hypotheses are:

H₀: σ₁² ≥ σ₂²

H₁: σ₁² < σ₂²

The statistic to test the variances ratio is the Stenecor's-F test. F_{H_0}=(\frac{S^2_1}{Sigma^2_1}) * (\frac{S^2_2}{Sigma^2_2} )~F_{n_1-1;n_2-1}

F_{H_0}= \frac{(12)^2}{(15)^2} * 1= 0.64

The p-value is:

P(F_{14;16}≤0.64)= 0.02

I hope it helps!

7 0
2 years ago
Traffic data revealed that 35 percent of automobiles traveling along a portion of an interstate highway were exceeding the legal
bija089 [108]
This is a typo and vaguely phrased. However, the closest to a direct solution is to think of it as follows: 35% of the cars are speeding. Out of these, 52% of the cars are also speeding. Hence, the result of cars that are both speeding and speed cars is 0.52*0.35=0.182
3 0
1 year ago
Read 2 more answers
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