g The completion times for a job task range from 11.8 minutes to 19.4 minutes and are thought to be uniformly distributed. What
1 answer:
Answer: 0.5263
Step-by-step explanation:
Given : The completion times for a job task range from 11.8 minutes to 19.4 minutes .
The density function for uniform distribution function for interval [a,b] :-
Then the density function for the given situation:-
The required interval :
Now, the probability that it will require between 12.8 and 16.8 minutes to perform the task will be :-
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Answer:
The answer is 23 years.
Step-by-step explanation:
We will use the formula :
Here P = 220
r = 3%
A = 400
Putting these values in the formula we get,
Taking log on both sides,
ln(1.03)t=ln 2
t=23.44 or rounding to nearest, t=23 years
The graph of the function can be shown as below.
Answer:
The coordinates of B is (3, - 5)
Step-by-step explanation:
A(6, 1)
C(2, -7)
Coordinates of point B such that AB = 1/3 × BC
Hence we have;
Therefore BC = 3/4 × AC
Hence, AB = 1/3 × BC = 1/3 × 3/4 × AC = 1/4 × AC
AC = √((6 - 2)² + (1 - (-7))²) = √(16 + 64) = √80 = 4·√5
AB = 1/4 × 4·√5 = √5
Therefore;
AB² = (x - 6)² + (y - 1)² = 5
Slope = (1 - (-7))/(6 - 2) = 2
Hence the y coordinate of B = -7 + sin(tan⁻¹(2)) ×√5 = -5
The x coordinate of B = 2 + cos(tan⁻¹(2)) ×√5 = 3
The coordinates of B = (3, - 5)
<em><u>Question:</u></em>
Juan Invest $3700 In A Simple Interest Account At A Rate Of 4% For 15 Years. How Much Money Will Be In The Account After 15 Years?
<em><u>Answer:</u></em>
There will be $ 5920 in account after 15 years
<em><u>Solution:</u></em>
<em><u>The simple interest is given by formula:</u></em>
Where,
p is the principal
n is number of years
r is rate of interest
From given,
p = 3700
r = 4 %
t = 15 years
Therefore,
<em><u>How Much Money Will Be In The Account After 15 Years?</u></em>
Total money = principal + simple interest
Total money = 3700 + 2220
Total money = 5920
Thus there will be $ 5920 in account after 15 years