Answer: Option 'c' is correct.
Step-by-step explanation:
Since we have given that
Mean of students' age = 24 years
Standard deviation of students' age = 3 years
Sample size = number of students = 350
So, according to options,
a. The shape of the sampling distribution is approximately normal.
It is true as n >30, we will use normal.
b. The mean of the sampling distribution is approximately 24-years old.
It is true as it is given.
c. The standard deviation of the sampling distribution is equal to 5 years.
It is not true as it is given 3 years.
Hence, Option 'c' is correct.
First of 30% of 2500kcal is 750kcal
if a male consumes 2.5 kcal then 750kcal / 2.5kcal = 300
but then we would need to know how many wheat are on one hectare of land.
Answer:
Step-by-step explanation:
Suppose the time required for an auto shop to do a tune-up is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - u)/s
Where
x = points scored by students
u = mean time
s = standard deviation
From the information given,
u = 102 minutes
s = 18 minutes
1) We want to find the probability that a tune-up will take more than 2hrs. It is expressed as
P(x > 120 minutes) = 1 - P(x ≤ 120)
For x = 120
z = (120 - 102)/18 = 1
Looking at the normal distribution table, the probability corresponding to the z score is 0.8413
P(x > 120) = 1 - 0.8413 = 0.1587
2) We want to find the probability that a tune-up will take lesser than 66 minutes. It is expressed as
P(x < 66 minutes)
For x = 66
z = (66 - 102)/18 = - 2
Looking at the normal distribution table, the probability corresponding to the z score is 0.02275
P(x < 66 minutes) = 0.02275
Benchmark are numbers that are used as standards to which the rest of the data is compared to. When counting numbers using a number line, the benchmark numbers are the intervals written on the axis. For benchmark numbers of 10, the number line on top of the attached picture is shown. Starting from 170, the tick marks are added by 10, such that the next numbers are 180, 190, 200, and so on and so forth. When you want to find 410, just find the benchmark number 410.
The same applies to benchmark numbers in intervals of 100. If you want to find 170, used the benchmark numbers 100 and 200. Then, you estimate at which point represents 170. For 410, you base on the benchmark numbers 400 and 500.
