Answer:
6, 6w, 3w, z and w.
Step-by-step explanation:
The common factors are those values that can divide 18w and 30wz perfectly.
Take a look at 6, 6 can divide both perfectly to give 3w and 5wz respectively.
We move on to 6w, this can also work perfectly to yield 3 and 5z.
6xz is not a factor as both values do not contain any x term.
3z is not a factor. Although 30wz has a z term, 18w does not.
3w is a factor as it can give 10z and 6 when used to divide the terms.
Z is not a factor as the 18w term does not contain a z term.
10w is not a term as it can not divide 18w perfectly
w is a term as it can divide both 18w and 30wz perfectly to yield 18 and 30z respectively.
Answer:
Step-by-step explanation:
a) = 46.2 X 10∧-1
=0.462
b) = 5.7 x 10∧-6
= 0.00057
Answer:
Step-by-step explanation:
This is one minus the probability that all the girls audition for different roles. The total number of ways of assigning roles to the girls is 12^7, because to each of the 7 girls, you have a choice of 12 roles.
Then if each girl is to receive a different role, then there are 12!/5! possibilities for that. If you start assigning roles to the girls, then for the first girl, there are 12 choices, but for the next you have to choose one of the 11 different ones, so 11 for the next, and then one of the 10 remaining for the next etc. etc., and this is 12*11*10*...*6 = 12!/(12-7)! =12!/5!
The probability that a random assignment of one of the 12^7 roles would happen to be one of the 12!/5! roles where each girl has a different role, is
(12!/5!)/12^7 = 12!/(12^7 5!)
Then the probability that two or more girls addition for the same part is the probability that not all the girls are assigned different roles, this is thus:
1 - 12!/(12^7 5!)
There are 12 different ways to organize your schedule
There are 2 English classes
There are 3 math classes
There are 3 history classes
Take 2x3x3 and you get 12
