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2 years ago

If two or more polygons are congruent, which statement must be true about the polygons? Read all of the choices before deciding.

Mathematics

2 answers:

SSSSS [86.1K]2 years ago

6 0

Answer:

if you have to choose more than on it will be option B. A,B,and E

Step-by-step explanation:

i had the same question asked

hodyreva [135]2 years ago

5 0

The best correct answer is option E. If two or more polygons are congruent, then rigid transformations can be used to map one polygon onto the other. <span>Two figures are said to be congruent when they have the same shape and size or if one object is a mirror image of the other object.</span>

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a local charity held a crafts fair selling donated,handmade items. Total proceeds from the sale were $1,875. A total of 95 items

Lana71 [14]

15x+25y=1875
Let
y=95-x
15x+25 (95-x)=1875
Solve for x
15x+2375-25x=1875
15x-25x=1875-2375
-10x=-500
X=500/10
X=50 the number of $15 items

Y=95-50=45 the number of $25 items

5 0

2 years ago

Tiana has already taken 1 page of notes on her own, and she will take 1 page during each hour of class. In all, how many hours w

Novosadov [1.4K]

Answer:

<u>42 Hours.</u>

Step-by-step explanation:

As an equation where y is the total pages and x is hours of class:

y=1+1x since she started with 1 page and does 1 page per hour.

Setting the total pages she needs as 43 (y=43) we get:

43=1+1x

Subtract one on both sides

42=1x

The 1 doesn't need to be written so

x=42

Therefore, it'll take her 42 hours to write all those notes.

4 0

2 years ago

A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe

xxMikexx [17]

Answer:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

Step-by-step explanation:

For the random variable $N_1$ we define the possible values for this variable on this case $[1,2,3,4,5]$ . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

$5C2 = \frac{5!}{2! (5-2)!}= \frac{5*4*3!}{2! 3!}= \frac{5*4}{2*1}=10$

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable $N_1$ like this:

$P(N_1 = a) = \frac{5-a C 1}{5C2}$

For the distribution of $N_2$ we need to take in count that we are finding a conditional distribution. $N_2$ given $N_1 =a$ , for this case we see that $N_2 \in [1,2,...,5-a]$ , so then exist $5-a C 1$ ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

$P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}$

And if we want to find the joint probability we just need to do this:

$P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)$

And if we multiply the probabilities founded we got:

$P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}$

8 0

2 years ago

Assume that two marbles are drawn without replacement from a box with 1 blue, 3 white, 2 green, and 2 red marbles. find the prob

navik [9.2K]

Before I answer the question i am going to start with the blue Marble you would have a 1/8 chance of drawing the blue marble from the box and after that you would have a 3/7 of drawing a white marble because you did not replace the blue marble and I hope this help.

8 0

2 years ago

Julie is a math tutor. She charges each student $210 for the first 7 hours of tutoring and $20 for each additional hour. When th

trasher [3.6K]

I'm sorry I do not know how to set up the equation but I do know it's 17 hours because 7(30)= 210 and 10(20)= 200 and 200+210=410

5 0

2 years ago