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2 years ago

What is the slope of a line perpendicular to the line whose equation is 3x-12y=2163x−12y=216.

Mathematics

2 answers:

zubka84 [21]2 years ago

8 0

Answer:

Slope (m) = 3

Step-by-step explanation:

Here 3x-12y-216=0

Reducing into slope intercept form

-12y= -3x + 216

12y = 3x - 216

Which is in the form of, y = mx + c

Slope (m) = 3

Keith_Richards [23]2 years ago

5 0

Answer:

Deleted account

Step-by-step explanation:

Here 3x-12y-216=0

Reducing into slope intercept form

-12y= -3x + 216

12y = 3x - 216

Which is in the form of, y = mx + c

Slope (m) = 3

Step-by-step explanation:

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Susan works as a hostess where she makes $8.75 per hour. She also babysits and earns $10.00 per hour. Last week she made $165.00

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Answer:

6 hours as a babysitter and 12 hours as a hostess

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2 years ago

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Kim solved the equation below by graphing a system of equations. log2(3x-1)= log4(x+8) What is the approximate solution to the e

kifflom [539]

Answer:

(1.35, 1.6)

Step-by-step explanation:

A screenshot of the graph is attached.

Once we graph the equations $y=\log_2(3x-1)$ and $y=\log_4(x+8)$ , the solution to this system will be their intersection point.

Tracing the graph on the calculator, we see that the point of intersection is at about (1.35, 1.6).

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1 year ago

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Let Xn be the random variable that equals the number of tails minus the number of heads when n fair coins are flipped. What is t

Firlakuza [10]

Answer:

the expected value of Xn , E(Xn) = 0 and the variance σ²(Xn) = n*(1-2n)

Step-by-step explanation:

If X1= number of tails when n fair coins are flipped , then X1 follows a binomial distribution with E(X1) = n*p , p=0,5 and the number of heads obtained is X2=n-X1

therefore

Xn =X1-X2 = X1- (n-X1) = 2X1-n

thus

E(Xn) =∑ (2*X1-n) p(X1) = 2*∑[X1 p(X1)] -n∑p(X1) = 2*E(X1)-n = 2*n*p--n= 2*n*1/2 -n = n-n =0

the variance will be

σ²(Xn) = ∑ [Xn - E(Xn)]² p(Xn) = ∑ [(2X1-n) - 0 ]² p(X1) = ∑ (4*X1²-4*X1*n+n²) p(X1) = = 4*∑ X1²p(X1) - 4n ∑X1 p(X1) - n²∑p(X1) = 2*E(X1²) -4n*E(X1)- n²

since

σ²(X1) = n*p*(1-p) = n*0,5*0,5=n/4

and

σ²(X1) = E(X1²) - [E(X1)]²

n/4 = E(X1²) - (n/2)²

E(X1²) = n(n+1)/4

therefore

σ²(Xn) = 4*E(X1²) -4n*E(X1)- n² = 4*n(n+1)/4 - 4*n*n/2 - n² = n(n+1) - 2n² - n²

= n - 2n² = n(1-2n)

σ²(Xn) = n(1-2n)

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1 year ago

on a sunny day liam decided to walk to his grandmother's house. After walking for a while at a rate of 3 mph, Liam realized that

inna [77]

Answer:

the answer is 10

Step-by-step explanation:

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1 year ago

Solve the radical equation. square root 6n-11= n – 3 Which solution is extraneous? A.)2

Anvisha [2.4K]

ANSWER

D) 10

EXPLANATION

We want to solve the radical equation,

$\sqrt{6n - 11} = n - 3$

Square both sides,

$6n - 11 = (n - 3) ^{2}$

Expand brackets on right hand side,

$6n - 11 = {n}^{2} - 6n + 9$

Rewrite in general quadratic equation form,

${n}^{2} - 12n + 20 = 0$

Factor to obtain,

$(n - 2)(n - 10) = 0$

Apply the zero product principle to get,

$n = 2 \: or \: n = 10$

We put n=2 into the equation to get,

$\sqrt{6(2) - 11} = 2 - 3$

$1 = - 1$

This statement is false, hence 2 is an extraneous solution

We put n=10, to get

$\sqrt{6(10) - 11} = 10 - 3$

$\sqrt{49} = 7$

$7 = 7$

This is true, hence the only solution is
$n = 10$

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2 years ago

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