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earnstyle [38]
2 years ago
10

Brian set a goal to horseback ride more than 6 miles. The horse he rode averaged a speed of 4.6 miles per hour. A 2-column table

with 4 rows titled Brian's Activity time (hours). Column 1 has entries hiking, mountain biking, horseback riding, cross-country skiing. Column 2 has entries 3, 1.45, 1.2, 0.75. Brian rode miles. Did he reach his goal?
Mathematics
2 answers:
Firdavs [7]2 years ago
6 0

Answer:

BRIAN DID NOT REACH HIS GOAL! Brian rode 5.52 miles!

Step-by-step explanation:

Pepsi [2]2 years ago
5 0

Answer:6.4

Step-by-step explanation:

Column 1                              Column 2

hiking                                             3

mountain biking                         1.45

horseback riding                         1.2

cross-country skiing                  0.75

3+1.45+1.2+0.75=6.4

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Answer:

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Step-by-step explanation:

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2 years ago
P=100a÷t solve for a
pishuonlain [190]

<u><em>a=1/100pt is the correct answer.</em></u> First you had to multiply by t from both sides of equation, and it gave us, ⇒ pt=100a. And then you had to flip an equation, and it gave us, ⇒100a=pt. You can also divide by one-hundred (100) from both sides of equation, and it gave us, \frac{100a}{100}=\frac{pt}{100}. And finally, and it gave us the answer is a=1/100pt is the final answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

8 0
2 years ago
Read 2 more answers
Match the following items by evaluating the expression for x = -6.
Kryger [21]

Step-by-step explanation:

Put the value of x = -6 to all expressions:

x^{-2}=(-6)^{-2}=\dfrac{1}{(-6)^2}=\dfrac{1}{6}\qquad\text{used}\ a^{-n}=\dfrac{1}{a^n}\\=====================\\x^{-1}=(-6)^{-1}=\dfrac{1}{(-6)^1}=-\dfrac{1}{6}\\=====================\\x^0=(-6)^0=1\qquad a^0=1\ \text{for all real numbers except 0}\\=====================\\x^1=(-6)^1=-6\qquad a^1=a\ \text{for all real numbers}\\=====================\\x^2=(-6)^2=36

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It depends on how b approaches 0

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On the other side, if b is negative and gets closer to zero, then 1/b will be negative and those negative values will decrease without bound. So 1/b approaches negative infinity if we approach 0 on the left (or negative) side.

The graph of y = 1/x shows this. See the diagram below. Note the vertical asymptote at x = 0. The portion to the right of it has the curve go upward to positive infinity as x approaches 0. The curve to the left goes down to negative infinity as x approaches 0.

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