Answer:
Step-by-step explanation:
Hello!
You need to construct a 95% CI for the population mean of the length of engineering conferences.
The variable has a normal distribution.
The information given is:
n= 84
x[bar]= 3.94
δ= 1.28
The formula for the Confidence interval is:
x[bar]±
*(δ/n)
Lower bound(Lb): 3.698
Upper bound(Ub): 4.182
Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242
I hope it helps!
He drew a scalene triangle
A scalene triangle is where all side measure and all angle measure are different.
Answer:
x = 8
y = 146
Error = 4.86%
Step-by-step explanation:
Number of business class passenger = x
and the economy class passenger = y
Total number of passengers = 154
x + y = 154 ------(1)
Cost of business class tickets and economy class tickets are €320 and €85 respectively.
Total amount received by airlines is €14970.
320x + 85y = 14970
64x + 17y = 2994 --------(2)
Multiply equation (1) by 17 and subtract from equation (2)
(64x + 17y) - (17x + 17y) = 2994 - 2618
47x = 376
x = 8
From equation (1),
8 + y = 154
y = 154 - 8
y = 146
Airline officer wrote down the amount received as €14270
Then difference from the actual amount received = 14970 - 14270
= €700
% Error = 
= 
= 4.676
≈ 4.68%
Therefore, x = 8 and y = 146
and % error = 4.68%
Answer:
Triangles QUT and SVR are congruent because the defining two sides and an included angle of triangles QUT and SVR are equal
Step-by-step explanation:
Here we have QT = SR and
QV = SU
Therefore,
QT = √(UT² + QU²)........(1)
RS = √(VS² + RV²)..........(2)
Since QS = QU + SU = QV + VS ∴ QU = VS
Therefore, since SR = QT and QU = VS, then from (1) and (2), we have UT = RV
Hence since we know all sides of the triangles QUT and SVR are equal and we know that the angle in between two congruent sides of the the triangles QUT and SVR that is the angle in between sides QU and UT for triangle QUT and the angle in between the sides RV and VS in triangle SVR are both equal to 90°, therefore triangles QUT and SVR are congruent.
Answer: = ( 0.411, 0.409)
Therefore at 95% confidence interval (a,b) = (0.411, 0.409)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean gain x = 0.41
Standard deviation r = 0.016
Number of samples n = 1000
Confidence interval = 95%
z(at 95% confidence) = 1.96
Substituting the values we have;
0.41+/-1.96(0.016/√1000)
0.41+/-1.96(0.000506)
0.41+/-0.00099
0.41+/-0.001
= ( 0.411, 0.409)
Therefore at 95% confidence interval (a,b) = (0.411, 0.409)
