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ioda
2 years ago
15

To complete one round of a jogging track, Samantha took 1.52 minutes. Which expression below represents the time taken by Samant

ha to complete 3 rounds of the track?
Mathematics
2 answers:
OleMash [197]2 years ago
8 0
As there is no sample expressions which could be the given answer we will solve it by the equation

(amount of time it takes to complete one round)*(number of rounds completed)=

We know that it took Samantha 1.52 minutes to go around once and assume that she continues this pace for 3 rounds. To solve for this we plug in our numbers into our equation.

1.52*3=<span>4.56</span> minutes to complete 3 rounds.

Does that answer your question?
icang [17]2 years ago
6 0
1.52 × 3 = 4.56 minutes
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Suppose the function F(c) represents the earnings of a volleyball team from selling c cupcakes. They are selling each cupcake fo
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Answer:

The variable c represents the domain as it is the independent variable.

The domain of the function F(c) is given by c ≥ 0.

So, only positive values for the input make sense.

The upper limit of the domain is +∞ and lower limit is 0.

It is not possible for the team to earn $50.50 as it will be only multiple of 2.

Step-by-step explanation:

If F(c) represents the earning of a volleyball team from selling c cupcakes and each cupcake costs $2 each, then the equation that models the situation is  

F(c) = 2c ..... (1)

The variable c represents the domain as it is the independent variable. (Answer)

The domain of the function F(c) is given by c ≥ 0. (Answer)

So, only positive values for the input make sense. (Answer)

The upper limit of the domain is +∞ and the lower limit is 0. (Answer)

It is not possible for the team to earn $50.50 as it will be only multiple of 2. (Answer)

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1 year ago
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6.In a sample of 131 women with cosmetic dermatitis from using eye shadow, 12 were diagnosed with a nickel allergy. In a sample
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Answer:

a) 0.0916 - 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.0422

0.0916 + 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.1410

So then we can conclude that the true proportion of women with cosmetic dermatitis from using eye shadow at 95% of confidence is between (0.0422 and 0.1410)

b) \hat p = \frac{25}{250}= 0.1

0.1 - 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.0628

0.1 + 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.1372

So then we can conclude that the true proportion of women with cosmetic dermatitis from using mascara at 95% of confidence is between (0.0628 and 0.1372)

c) For this case we see that both confidence intervals contains the value of 0.12 so then we can't conclude that only one group is referenced at the significance level of 0.05 used.

Step-by-step explanation:

Part a

The estimated proportion of women with cosmetic dermatitis from using eye shadow is given by:

\hat p =\frac{12}{131}= 0.0916

The confidence  interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the proportion is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing we got:

0.0916 - 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.0422

0.0916 + 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.1410

So then we can conclude that the true proportion of women with cosmetic dermatitis from using eye shadow at 95% of confidence is between (0.0422 and 0.1410)

Part b: A 95% confidence interval for the women with cosmetic dermatitis from using mascara

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0.1 - 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.0628

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So then we can conclude that the true proportion of women with cosmetic dermatitis from using mascara at 95% of confidence is between (0.0628 and 0.1372)

Part c: Suppose you are informed that the true proportion with a nickel allergy for one of the two groups (eye shadow or mascara) is .12. Can you determine which group is referenced? Explain.

For this case we see that both confidence intervals contains the value of 0.12 so then we can't conclude that only one group is referenced at the significance level of 0.05 used.

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Can someone help me ?
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