Answer: 5225472000
Step-by-step explanation:
Given : The number of bulls = 6
The number of horses = 10
Since Aidan needs to place them in a line of 16 paddocks, and the bulls cannot be placed in adjacent paddocks .
Also there are two ways to arrange the group pf bulls and horses.
Then , the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks will be :_
Hence, the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks =5225472000
Answer:
Explanation:
The number of different ways in which the<em> two armadillos</em> would be at the ends of the row is 2:
The number of different combinations in which<em> two of the three aardvarks </em>can sit at the ends of the row is P(3,2):
Therefore, there are 2 + 6 = 8 different ways in which the two animlas on the ends of the row were both armadillos or both aardvarks.
Now calculate the total number of different ways in which the animals can sit. It is P(5,5):
Thus, <em>the probability that the two animals on the ends of the row were both armadillos or both aardvarks</em> is equal to the number of favorable outputs divided by the total number of possible outputs:
c^2 = a^2 + b^2 - 2*ab*Cos(C)
c = 16; a = 17; b = 8 (what you call a and b don't really matter. c does). Substitute.
16^2 = 17^2 + 8^2 - 2*17*8*Cos(C) Add the first 2 on the right.
256 = 289 + 64 - 282*cos(C)
256 = 353 - 282*cos(C)
Whatever you do, don't do any more combing on the right side. Subtract 353 from both sides.
-97 = -282 * cos(C )
Divide by 282
0.34397 = cos(C)
cos-1(0.34397) = C ; C = 69.88 degrees.
Do you need more help on this question? All of these are done the same way.
Answer:
$23.40
Step-by-step explanation:
You have to subtract $39.75 by $16.35 as $39.75 is the total and we have to find out how much the bracelet is. There is also no regrouping.
