M<1≠m<2
m<4≠m<6
m<3 + m<5 = 180° ≠ 90°
m<7≠m<8
Answer:
none of them.
Answer:
none of them are greater than 1.45
Answer:
The data provide strong evidence that young men weigh more on average than old men in the U.S
Step-by-step explanation:
Given :
The null hypothesis ; H0 : μ1 = μ2
The alternative hypothesis ; H1 : μ1 > μ2
T score = 5.3 ; Pvalue = < 0.0001
The decision region :
If Pvalue < α ; We reject the Null
If Pvalue > α ; We fail to reject the Null
When the α - level isn't stated, we usually assume a α - level of 5%
However, even at lower alpha level of 1% = 0.01 ;
The Pvalue < α
Hence, we can conclude that there is significant evidence that there is difference in the mean weight of young men and old men in the U.S
If there is a triangle with Sid a and b then sina b/✓a2+b2and seven=✓a2+b2/a
Answer:
A = πr² ← r is the radius and r = \frac{1}{2} d ← d is the diameter
Hence
π (\frac{1}{2} d)² = A, that is
\frac{d^2\pi }{4} = A ( multiply both sides by 4 )
d²π = 4A ( divide both sides by π )
d² = \frac{4A}{\pi } ( take the square root of both sides )
d = \sqrt{\frac{4A}{\pi } }