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Fofino [41]
2 years ago
11

Wezi has sixty-three $5-bills to the bank to exchange them for $20-bills. How many $20-bills does Wezi get? Is there money left

over? explain
Mathematics
1 answer:
In-s [12.5K]2 years ago
5 0

Answer:

A. Wezi will get fifteen (15) $20-bills.

B. There will be $15 left.

Step-by-step explanation:

A. We have been given that Wezi has sixty-three $5 bills.

Let us find the total amount of money that Wezi has by multiplying 63 by 5.

\text{Total amount of money Wezi has}=63\times\$5

\text{Total amount of money Wezi has}=\$315

Therefore, Wezi has $315.

Since Wezi wants to exchange her total money of $5 bills with $20 bills, so let us divide total amount of money by 20.

\text{The number of \$20 bills}=\frac{\$315}{\$20}

\text{The number of \$20 bills}=15.75

Since we cannot 0.75 of a $20 bill, so Wezi will get 15 $20-bills.

We can see that 315 is not completely divisible by 20, so let us subtract greatest multiple of 20 from 315.

We can see 15\times 20=300, so upon subtracting 300 from 315 we will get,

\$315-\$300=\$15

Therefore, there will be $15 left.

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Sladkaya [172]

It is -11.34

-$68.04 divide by 6 is -$11.34, so instead of 11.34, it's -11.34

3 0
2 years ago
Using the quadratic formula to solve 11x2 – 4x = 1, what are the values of x? StartFraction 2 Over 11 EndFraction plus-or-minus
slamgirl [31]

Answer:

x=\frac{2}{11}\pm\frac{\sqrt{15}} {11}

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

11x^{2} -4x=1  

equate to zero

11x^{2} -4x-1=0  

so

a=11\\b=-4\\c=-1

substitute in the formula

x=\frac{-(-4)\pm\sqrt{-4^{2}-4(11)(-1)}} {2(11)}

x=\frac{4\pm\sqrt{60}} {22}

x=\frac{4\pm2\sqrt{15}} {22}

x=\frac{2\pm\sqrt{15}} {11}

x=\frac{2}{11}\pm\frac{\sqrt{15}} {11}

therefore

StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 15 EndRoot Over 11 EndFraction

7 0
2 years ago
Read 2 more answers
A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc
lisov135 [29]

Answer:

The answer is option (C), One cement bridge post weighs 9,135 pounds

Step-by-step explanation:

Step 1: Get the total volume of a cement bridge post

The cement bridge post is in the shape of a cuboid, therefor the volume of the cement bridge post can be expressed as;

Volume of cement bridge post=Base area×Length

where;

Base area=(24^2) inches square

1 foot=12 inches

Convert 24 inches to foot=24/12=2^2=4 feet²

Length=15 feet and 9 inches

1 foot=12 inches

Convert 9 inches to foot=9/12=0.75 feet

Total length=(15+0.75)=15.75 feet

replacing;

Volume of cement bridge post=(4×15.75)=63 cubic feet

Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

Total weight of the cement bridge post=Weight per cubic foot×total volume of the cement bridge post

where;

Weight per cubic foot=145 pounds per cubic foot

Total volume of the cement bridge post=63 cubic feet

replacing;

Total weight of the cement bridge post=(145×63)=9,135 pounds

One cement bridge post weighs 9,135 pounds

8 0
2 years ago
Ray Np is an angle bisector of angle MNQ and measure of Angle PNQ = 2x+1. Find the measure of angle MNQ. If The measure of MNQ=x
Step2247 [10]
Refer to the diagram below.

Because ray NP bisects ∠MNQ, therefore
∠MNP = ∠PNQ = 2x + 1.
Therefore
∠MNQ = 2*∠PNQ = 2(2x + 1) = 4x + 2.

Because ∠MNQ is given as x² - 10, therefore
x² - 10 = 4x + 2
x² - 4x - 12 = 0
(x + 2 )(x - 6) = 0
x = -2, or x = 6

When x = -2, 
∠MNQ = 4*(-2) + 2 = -6°
This answer is not acceptablle, therefore x = -2 should be rejected.

When x = 6,
∠MNQ = 4*6 + 2 = 26°

Answer: x = 6, and ∠MNQ = 26°

7 0
2 years ago
Given the line below.
Yanka [14]

We have to write the equation of the line, in point-slope form. Given an identified point (x1, y1) as the point (-2, 2). So that means x1=-2 and y1=2

Value of slope "m" is not given so i will keep using "m" for the slope. In case value of slope m is given in the problem then you can plug that number in place of m.

Point slope formula is given by:

y-y_1=m\left(x-x_1\right)

plug the given values into above formula :


y-\left(2\right)=m\left(x-\left(-2\right)\right)

y-2=m\left(x+2\right)

so the required answer in point slope form is y-2=m\left(x+2\right)

8 0
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