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Svet_ta [14]
2 years ago
15

charmaine and tesha each have a number of cards, in the ratio 2:3. tesha and holly have a number of cards in the ratio 2:1. if t

esha has 4 more cards than charmaine, how many cards does holly have?
Mathematics
1 answer:
Sav [38]2 years ago
3 0
C:t=2:3
t:h=2:1

multiply first equation by 2 and 2nd by 3
c:t=4:6
t:h=6:3
so
c:t:h=4:6:3

if t is 4 more than c
t is 6 units and c is 4
6-4=2
so 4=2 units
2=1 unit

hollly is 3 units
3*2=6
holly has 6 cards
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Answer:

Paula get \$144 and Kawai get \$168.

Step-by-step explanation:

Given: Paula and Kawai shared \$312 in the ratio of 6:7.

To find: How much money  did each person get?

Solution:

We have,

Paula and Kawai shared \$312 in the ratio of 6:7.

So, let Paula get \$6x and Kawai get \$7x.

As per the question,

6x+7x=312

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Therefore, Paula get 6\times 24=\$144, and Kawai get 7\times 24=\$168.

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To bill customers for water usage, one city converts the number of gallons used into units. This relationship is represented by
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Find a matrix representation of the transformation L(x, y) = (3x + 4y, x − 2y).
mario62 [17]

Answer:

\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}3&1\\4&-2\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]

Step-by-step explanation:

The general matrix representation for this transformation would be:

\left[\begin{array}{cc}x&y\end{array}\right] * A = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]

As the matrix A should have the same amount of rows as columns in the firs matrix and the same amount of columns as the result matrix it should be a 2x2 matrix.

\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]

Solving the matrix product you have that the members of the result matrix are:

3x+4y = a*x + c*y

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So the matrix A should be:

\left[\begin{array}{cc}3&1\\4&-2\end{array}\right]

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