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Svet_ta [14]
1 year ago
15

charmaine and tesha each have a number of cards, in the ratio 2:3. tesha and holly have a number of cards in the ratio 2:1. if t

esha has 4 more cards than charmaine, how many cards does holly have?
Mathematics
1 answer:
Sav [38]1 year ago
3 0
C:t=2:3
t:h=2:1

multiply first equation by 2 and 2nd by 3
c:t=4:6
t:h=6:3
so
c:t:h=4:6:3

if t is 4 more than c
t is 6 units and c is 4
6-4=2
so 4=2 units
2=1 unit

hollly is 3 units
3*2=6
holly has 6 cards
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1 year ago
A charity receives 2025 contributions. Contributions are assumed to be mutually independent and identically distributed with mea
uysha [10]

Answer:

The 90th percentile for the distribution of the total contributions is $6,342,525.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums of size n, the mean is \mu*n and the standard deviation is s = \sqrt{n}*\sigma

In this question:

n = 2025, \mu = 3125*2025 = 6328125, \sigma = \sqrt{2025}*250 = 11250

The 90th percentile for the distribution of the total contributions

This is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. Then

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

1.28 = \frac{X - 6328125}{11250}

X - 6328125 = 1.28*11250

X = 6342525

The 90th percentile for the distribution of the total contributions is $6,342,525.

3 0
1 year ago
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pashok25 [27]

Answer: y = -9

Step-by-step explanation:

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y = -9

7 0
2 years ago
If f(x) = 3 – 2x and 1/x+5, what is the value of (f/g)(8)? –169 –1 13 104
Basile [38]
I'm assuming that this is the complete question.
If f(x) = 3 – 2x and g(x)=1/(x+5), what is the value of (f/g)(8)? a) –169       b) –1      c) 13     d) 104
x = 8
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