Answer:
Paula get 
and Kawai get 
.
Step-by-step explanation:
Given: Paula and Kawai shared 
in the ratio of 
.
To find: How much money did each person get?
Solution:
We have,
Paula and Kawai shared in the ratio of .
So, let Paula get 
and Kawai get 
.
As per the question,
Therefore, Paula get 
, and Kawai get 
.
Hence, Paula get and Kawai get .
The reaction as an equation, using the abbreviation or the name of each two reactants and each of the three products is Adenosine Diphosphate + ATP = Pi.The equation in this question that use the name or the abbreviation is Adenosine Diphosphate + ATP = Pi. The answer in this question is Adenosine Diphosphate + ATP = Pi.
We are given equation g = 748u, where g is the total number of gallons of water used and u is the number of units.
We can see that the number of units of water being used by customers.
The number of units of water doesn't depend on the total number of gallons of water used.
Therefore, the number of units u is an independent variable.
The value of the total number of gallons is totally depends on the number of units used.
Therefore, the total number of gallons of water used g is a dependent variable.
So, we can conclude following statements:
1) g is the dependent variable.
2) u is the independent variable.
Well there's 10 minutes in the second part so first 48/2 is 24. Now 24/4 (since there's 4 people so far) is 6, now 6*6 because there's now 6 people in total so the final answer is 36 in 5 minutes
Answer:
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}3&1\\4&-2\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The general matrix representation for this transformation would be:
![\left[\begin{array}{cc}x&y\end{array}\right] * A = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
As the matrix A should have the same amount of rows as columns in the firs matrix and the same amount of columns as the result matrix it should be a 2x2 matrix.
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Solving the matrix product you have that the members of the result matrix are:
3x+4y = a*x + c*y
x - 2y = b*x + d*y
So the matrix A should be:
![\left[\begin{array}{cc}3&1\\4&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D)
