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2 years ago

HURRY UP!!!Right triangle QRS is pictured below.

Mathematics

2 answers:

fredd [130]2 years ago

5 0

Answer:

C. cos(31°) = RS/24.8

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relation between the adjacent side and the hypotenuse and the trig function of an angle:

Cos = Adjacent/Hypotenuse

In the given triangle, the side adjacent to the 31° angle is RS. The hypotenuse is marked as 24.8. So, the relationship you seek is ...

cos(31°) = RS/24.8 . . . . . matches choice C

Gemiola [76]2 years ago

4 0

Answer:

Step-by-step explanation:

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The ball bearing have volumes of 1.6cm cube and 5.4cm cube . Find the ratio of their surface area.

Korvikt [17]

Answer:

4/9

Step-by-step explanation:

The scale factor for the linear dimensions of the ball bearings will be the cube root of the volume scale factor:

k = ∛(1.6/5.4) = 2/3

Then the scale factor for the areas will be the square of this scale factor:

ratio of surface area = (2/3)² = 4/9

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The area is the product of two linear dimensions, so its scale factor is the product of the linear dimension scale factors. That is, the scale factor for area is the square of the linear dimension scale factor.

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2 years ago

Mrs. Varner deposited q dollars in a bank account that has been earning annual interest. The total value of the account is based

Ray Of Light [21]

The answer is f(x) = q * 1.025x + 5, do you have that?

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2 years ago

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The diagram above contains contradictory information. Explain the contradiction.

Anarel [89]

Since these are alternate interior angles, they should be congruent. Equating the measures given:
-x - 30 = 5x - 30
x = 0
However, this is not true, since the diagram clearly shows that there is a positive angle between them.
The best answer is choice B.

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2 years ago

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An experiment was performed to compare the abrasive wear of two different laminated materials. Twelve pieces of material 1 were

vladimir1956 [14]

Answer:

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

There is significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units

Step-by-step explanation:

Step:-(1)

Given data the samples of material 1 gave an average (coded) wear of 85 units with a sample standard deviation of 4

Mean of the first sample x₁⁻ =85

standard deviation of the first sample S₁ = 4

Given data the samples of material 2 gave an average of 81 and a sample standard deviation of 5.

Mean of the first sample x₂⁻ =81

standard deviation of the first sample S₂ = 5

Step :-2

Null hypothesis: H₀: there is no significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Alternative hypothesis :H₁: there is significance difference between that the abrasive wear of material 1 exceeds that of material 2 by more than 2 units

Assume the populations to be approximately normal with equal variances.σ₁² =σ₂²

The test statistic

$Z= \frac{x_{1} -x_{2} }{\sqrt{\frac{S^2_{1} }{n_{1} } +\frac{S^2_{2} }{n_{2} } } }$

Given n₁=n₂=60.

$Z= \frac{85-81 }{\sqrt{\frac{(4)^2 }{60 } +\frac{5^2 }{60} } }$

On calculation, we get

Z = $\frac{4}{\sqrt{0.6833} }$

z = 4.8389

The tabulated value Z =1.96 at 0.05 level of significance.

The calculated value Z= 4.8389> 1.96 at 0.05 level of significance.

The null hypothesis is rejected.

Conclusion:-

there is significance difference between that the abrasive wear of material 1 not exceeds that of material 2 by more than 2 units.

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2 years ago

An architect designs a rectangular flower garden such that the width is exactly two thirds of the length of 270 feet of an antiq

bezimeni [28]

Width=180
Area=48600
Perimeter=900

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2 years ago