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Natali [406]
1 year ago
9

HURRY UP!!!Right triangle QRS is pictured below.

Mathematics
2 answers:
fredd [130]1 year ago
5 0

Answer:

  C.  cos(31°) = RS/24.8

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relation between the adjacent side and the hypotenuse and the trig function of an angle:

  Cos = Adjacent/Hypotenuse

In the given triangle, the side adjacent to the 31° angle is RS. The hypotenuse is marked as 24.8. So, the relationship you seek is ...

  cos(31°) = RS/24.8 . . . . . matches choice C

Gemiola [76]1 year ago
4 0

Answer:

Step-by-step explanation:

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James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
2 years ago
Chase tried to solve an equation step by step. \qquad\begin{aligned} \dfrac13(g-3)&=3\\\\ \\ g-3&=9&\green{\text{Ste
Sonbull [250]

Answer:cant really help with that because the question is messed up sorry

Step-by-step explanation:

6 0
2 years ago
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Without any equipment you can see stars that are 2,800,000 light years away. By looking at through a small telescope you can see
Stells [14]

Answer:

hi

Step-by-step explanation:

4 0
1 year ago
In regional spelling bee, the 8 finalists consist of 3 boys and 5 girls. Find the number of sample point the sample space S for
Minchanka [31]

Answer:

i) There are 40320 possible orders

ii) There are 336 possible orders for the first 3 positions.

Step-by-step explanation:

Given: The number of finalists = 8

The number of boys = 3

The number of girls = 5

To find the number of sample point the sample space S for the number of possible orders, we need to find factorial of 8!

The number of possible orders = 8!

= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8

= 40320

ii) From all 8 finalist, we need to choose first 3 position. Here the order is important. So we use permutation.

nPr =\frac{n!}{(n - r)!}

Here n = 8 and r = 3

Plug in n =8 and r = 3 in the above formula, we get

8P3 = \frac{8!}{(8 - 3)!}

= \frac{8!}{5!} \\= \frac{1.2.3.4.5.6.7.8}{1.2.3.4.5}

= 6.7.8

= 336

So there are 336 possible orders for the first 3 positions.

3 0
2 years ago
The failure rate for a guided missile control system is 1 in 1,000. Suppose that a duplicate but completely independent control
olga_2 [115]

Answer:

<h2>The reliability is 0.999999.</h2>

Step-by-step explanation:

The failure rate for a guided missile control system is 1 in 1,000.

Hence, the probability that the missile will not fail is \frac{1000 - 1}{1000} = \frac{999}{1000}.

According to the new system, if the first fails, the second can take over.

There are two possibilities, either the first one will be fail or not.

If the first one will not fail, then the probability will be \frac{999}{1000} = 0.999.

If the first one will fail, then the probability will be \frac{999}{1000} \times\frac{1}{1000} = 0.000999.

The reliability of the modified missile is 0.999 + 0.000999 = 0.999999.

6 0
2 years ago
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