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rusak2 [61]
1 year ago
11

Tom has a water tank that holds 5 gallons of water.Tom uses water from a full tank to fill 6 bottles that each hold 16 ounces an

d a pitcher that holds 1/2 gallon.How many ounces of water are left in the water tank?
Mathematics
1 answer:
Rainbow [258]1 year ago
8 0
1/2 Gallon is equal to 64 ounces
16 x 6 = 96
96 + 64 = 160
5 gallons is equal to 640
640 - 160 = 480
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At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu
dangina [55]
If one is to choose among given choices and the order is not important, we use the concept of combination. First, we calculate for the sample space or number available since there is a total number of 12 electives and a student may choose 2 out of them.                           
S = 12C2
That is "the sample space is equal to combination of 12 taken 2". The answer to this is equal to 66. 

Next, we determine the number of outcomes. The equation will be,
                        O = (5C1) x (3C1) 
That is "outcome is equal to combination of 5 taken 1 times combination of 3 taken 1". This is equal to 15. The probability is equal to,
                        P = O/S

Substituting,
                        P = (15/66) = 0.227270
The answer to this item is the third choice. 
6 0
1 year ago
Read 2 more answers
Diana sold 336 muffins at the bake sale.Bob sold 287 muffins.Bob estimates that he sold 50 fewer muffins than Diana.how did he e
malfutka [58]

Step-by-step explanation:

Since we have given that

Number of muffins Diana sold at the bake sale = 336

Number of muffins Bob sold at the bake sale = 287

Now, here we are using the method of estimation i.e. rounding the integers to nearest ones.

By estimation, we get

Number of muffins Diana sold at the bake sale = 340

Number of muffins Bob sold at the bake sale = 290

So,

Difference between them is given by

340-290\\=50

Hence, Bob sold 50 fewer muffins than Diana.

3 0
1 year ago
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Daniel is printing out copies of a presentation. It takes 3 minutes to print a color copy and 1 minute to print a black-and-whit
Effectus [21]
Work the information to set inequalities that represent each condition or restriction.

2) Name the variables. 

c: number of color copies
b: number of black-and-white copies

3) Model each restriction:

i) <span>It takes 3 minutes to print a color copy and 1 minute to print a black-and-white copy.
</span><span>
</span><span>3c + b
</span><span>
</span><span>
</span><span>ii) He needs to print at least 6 copies ⇒ c + b ≥ 6
</span><span>
</span><span>
</span><span>iv) And must have the copies completed in no more than 12 minutes ⇒</span>

3c + b ≤ 12
<span />

4) Additional restrictions are c ≥ 0, and b ≥ 0 (i.e. only positive values for the number of each kind of copies are acceptable)

5) This is how you graph that:

i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.

ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.

iii) since c ≥ 0 and b ≥ 0, the region is in the first quadrant.

iv) The final region is the intersection of the above mentioned shaded regions.

v) You can see such graph in the attached figure.

6 0
1 year ago
Carly commutes to work, and her commute time is dependent on the weather. When the weather is good, the distribution of her comm
Stels [109]
We are given with
x1 = 20 min
s1 = 2 min

x2 = 30 min
s2 = 4 min

p = 0.9
Condition (x > 25)

We need to get the t-value between the two means and comparing it wit the t-value for the time of 25 minutes given that there is a 90% probability that the weather will be good. Simply use the t-test formula and use the t-test table to get the probability.
8 0
2 years ago
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Brad is hoping to package exactly 48 baseballs together. He sees the side of a box in his storeroom that is 2 x 3. What is he ho
lakkis [162]

The given dimensions of the base of the box are 2 x 3 units.

Let h be the height of the box.

So, the volume of the box = 2 x 3 x h ...(i)

The shape of baseball is spherical and one baseball fits in a cubical box having the minimum dimensions equal to the diameter of the spherical ball.

Assuming the diameter of the baseball is d units.

So, the volume occupied by one baseball= volume of the cubical box having the side d units.

=d^3 cubic units

So, the volume required to pack 48 baseballs

= 48 d^3 \cdots(ii)

Assuming that all the baseballs fit in the box, i.e peripheral balls in every horizontal and vertical layer touched the box as shown in the figure.

So, the length, 3 units and the width, 2 units, must be the integral multiple of the diameter, d units, of the baseball. i.e

The length, 3 = ad\cdots(iii)

The width, 2=bd\cdots(iv)

The height, h=cd\cdots(iv)

where a,b and c  belong to the natural number.

This required volume must be equals to the volume of the box.

From equations (i) and (ii),

2\times 3\times h=48d^3

 [from (iii) and (iv)]

\Rightarrow abhd^2=48d^3

\Rightarrow  h=\frac{48d^3}{6abd^2}

\Rightarrow  h=\frac{48}{ab}d

On comparing with the equation (iv)

c=\frac{48}{ab}\cdots(v)

Now, if the diameter of the baseball is unity,i.e, d=1 unit

( integer) and (integer) [from (iii) and (iv)]

(also an integer)  [from (v)]

Now, the height of the box,

h=8 \times 1= 8 unit.

Hence, the other dimension of the box, is 8 units corrosponding to the unity diameter of the baseball.

Note the height of the box depends on the diameter of the baseball, so it will have infinite possible value for different value of the diameter.

For example, the value of height for d=1 unit has been shown.

and another example may be if units, then (integer) and (integer)

(also an integer)  [from (v)]

Now, the height of the box,

h=2 \times 0.5= 1 unit. [from (iv)]

Here, the height of the box is 2 units corrosponding to 0.5 unit diameter of the baseball.

The possivle values of d can be taken for which a,b and c must be integers.

6 0
1 year ago
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