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rusak2 [61]
2 years ago
11

Tom has a water tank that holds 5 gallons of water.Tom uses water from a full tank to fill 6 bottles that each hold 16 ounces an

d a pitcher that holds 1/2 gallon.How many ounces of water are left in the water tank?
Mathematics
1 answer:
Rainbow [258]2 years ago
8 0
1/2 Gallon is equal to 64 ounces
16 x 6 = 96
96 + 64 = 160
5 gallons is equal to 640
640 - 160 = 480
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Joy makes 6.5 litres of soup, correct to the nearest 0.5 litre. She serves the soup in 280 ml portions, correct to the nearest 1
Levart [38]

Answer:

Joy definitely does have enough soup for 22 people.


Step-by-step explanation:

Upper Bound: 285ml  turn it to 0.285 L                      10÷2=5

280ml  :

Lower Bound: 275ml turn it  to 0.275 L

Upper Bound: 6.75 L                           0.5÷2=0.25

6.5 Litters  :

Lower Bound:6.25  L

6.75÷0.275=24.54 or 25  

6.25÷0.285=21.92 or 22

7 0
2 years ago
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Jacob spends 60 minutes in the gym every day doing freehand exercises and running on the treadmill. He runs on the treadmill 30
elixir [45]

Answer:

a.

x + y = 60

x = y + 30

b.

substitution:

(y + 30) = y = 60

2y + 30 = 60

2y = 30

y = 15

15 minutes for freehand

c.

No, because if he spends 40 minutes on the treadmill, he would have spent 10 minutes for freehand exercises. His total time in the gym would be 50 minutes, not 60.

8 0
2 years ago
33.32 divided by 9.8
kifflom [539]

Answer:

33.32 / 9.8 = 3.4;

Step-by-step explanation:


3 0
2 years ago
Given that tangent theta = negative 1, what is the value of secant theta, for StartFraction 3 pi Over 2 EndFraction less-than th
Rashid [163]

Answer:

sec(\theta)=\frac{2}{\sqrt{2} }=\sqrt{2}

Step-by-step explanation:

Start by noticing that the angle \theta is on the 4th quadrant (between \frac{3\pi}{2} and 2\pi. Recall then that in this quadrant the functions tangent and cosine are positive, while the function sine is negative in value. This is important to remember given the fact that tangent of an angle is defined as the quotient of the sine function at that angle divided by the cosine of the same angle:

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Now, let's use the information that the tangent of the angle in question equals "-1", and understand what that angle could be:

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-1=\frac{sin(\theta)}{cos(\theta)}\\-cos(\theta)=sin(\theta)

The particular special angle that satisfies this (the magnitude of sine and cosine the same) in the 4th quadrant, is the angle \frac{7\pi}{4}

which renders for the cosine function the value \frac{\sqrt{2} }{2}.

Now, since we are asked to find the value of the secant of this angle, we need to remember the expression for the secant function in terms of other trig functions: sec(\theta)=\frac{1}{cos(\theta)}

Therefore the value of the secant of this angle would be the reciprocal of the cosine of the angle, that is: sec(\theta)=\frac{2}{\sqrt{2} }=\sqrt{2}

6 0
2 years ago
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All side lengths of ΔJKL equal 2 units. A transformation maps ΔJKL to ΔJ'K'L'. The length of side J'K' is 5 units. Is this a rig
S_A_V [24]
No because at least one segment length is not preserved.
rigid means everything stays the same, but orientation sometimes changes.
5 0
2 years ago
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