An equation in the form
is the line
that goes through the origins and whose tangent equates
. In general, any equation in the form
is the equation of a line.
Answer:
68a+ab−1
Step-by-step explanation:
cancel out
Answer:
a) 0.9644 or 96.44%
b) 0.5429 or 54.29%
Step-by-step explanation:
a) The probability that at least 1 defective card is in the sample P(A) = 1 - probability that no defective card is in the sample P(N)
P(A) = 1 - P(N) .....1
Given;
Total number of cards = 140
Number selected = 20
Total number of defective cards = 20
Total number of non defective cards = 140-20 = 120
P(N) = Number of possible selections of 20 non defective cards ÷ Number of possible selections of 20 cards from all the cards.
P(N) = 120C20/140C20 = 0.0356
From equation 1
P(A) = 1 - 0.0356
P(A) = 0.9644 or 96.44%
b) Using the same method as a) above
P(A) = 1 - P(N) .....1
Given;
Total number of cards = 140
Number selected = 20
Total number of defective cards = 5
Total number of non defective cards = 140-5 = 135
P(N) = 135C20/140C20 = 0.457
From equation 1
P(A) = 1 - 0.4571
P(A) = 0.5429 or 54.29%
Work the information to set inequalities that represent each condition or restriction.
2) Name the
variables.
c: number of color copies
b: number of black-and-white copies
3)
Model each restriction:
i) <span>It
takes 3 minutes to print a color copy and 1 minute to print a
black-and-white copy.
</span><span>
</span><span>
3c + b</span><span>
</span><span>
</span><span>ii) He needs to print
at least 6 copies ⇒
c + b ≥ 6</span><span>
</span><span>
</span><span>iv) And must have
the copies completed in
no more than 12 minutes ⇒</span>
3c + b ≤ 12<span />
4) Additional restrictions are
c ≥ 0, and
b ≥ 0 (i.e.
only positive values for the number of each kind of copies are acceptable)
5) This is how you
graph that:
i) 3c + b ≤ 12: draw the line 3c + b = 12 and shade the region up and to the right of the line.
ii) c + b ≥ 6: draw the line c + b = 6 and shade the region down and to the left of the line.
iii) since c ≥ 0 and b ≥ 0, the region is in the
first quadrant.
iv) The final region is the
intersection of the above mentioned shaded regions.v) You can see such graph in the attached figure.
Answer:
A is incorrect! <u>B. should be the correct answer</u>
Step-by-step explanation
After some research, i found that the correct answer is most likely <u><em>B. a regression line and trend line are equivalent terms</em></u>
<em />
<em>A trendline and a regression can be the same.
</em>
<em>
A regression line is based upon the best fitting curve Y= a + bX Most often it’s a least-squares fit (where the squared distances from the points to the line (along the Y-axis) is minimized).
</em>
<em>
It can be quadratic or logistic or otherwise, but most often it is linear.
</em>
<em>
A trendline is often constructed by smoothing of the results, making it less peaked. (often by using a moving average); but can also come from ARIMA projections or curve fitting techniques (such as regression).</em>
<em />
Let me know if i helped you!
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