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LUCKY_DIMON [66]

2 years ago

15

17. A local university accepted 2,300 students out of 4,500 applicants for admission. What was the acceptance rate, expressed as

a percent?

1 answer:

Alona [7]2 years ago

3 0

The answer is 51%
Because you have to divide 2,300/4500=0.51 which gives you 51%

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Suppose two different methods are available for eye surgery. The probability that the eye has not recovered in a month is 0.002

umka21 [38]

Answer:

0.4007

Step-by-step explanation:

Let's define the following events:

A: method A is used

B: method B is used

NR: the eye has not recovered in a month

R: the eye is recovered in a month

The probability that the eye has not recovered in a month is 0.002 if method A is used, i.e., P(NR|A) = 0.002, so P(R|A) = 0.998.

When method B is used, the probability that the eye has not recovered in a month is 0.005, i.e., P(NR|B) = 0.005, so P(R|B) = 0.995.

40% of eye surgeries are done with method A, i.e., P(A) = 0.4

60% of eye surgeries are done with method B, i.e., P(B) = 0.6

If an eye is recovered in a month after surgery is done in the hospital, what is the probability that method A was performed? We are looking for P(A|R), then, by Bayes' Formula

P(A|R) = P(R|A)P(A)/(P(R|A)P(A) + P(R|B)P(B)) = 0.998*0.4/(0.998*0.4 + 0.995*0.6) = 0.4007

4 0

2 years ago

Paige works at a department store and has a commission rate of 3 percent. Her sales for the quarter were $4,596. If she earns $5

ANTONII [103]

How you would set this up would be as follows:

(50*30)+4,596*.03

The 50*30 is her earning $50 a day for 30 days. Then to find her commission earnings you multiply her sales of 4,596 times the commission rate of 3%(when you move the decimal place you get .03)

Add them together and you get her total amount earned of $1,637.88

Hope this helped!

6 0

2 years ago

Read 2 more answers

Suppose that the IQs of universityâ€‹ A's students can be described by a normal model with mean 140 and standard deviation 8 poi

AnnZ [28]

Answer:

0.0266, 0.9997,0.7856

Step-by-step explanation:

Given that the IQs of universityâ€‹ A's students can be described by a normal model with mean 140 and standard deviation 8 points. Also suppose that IQs of students from university B can be described by a normal model with mean 120 and standard deviation 11. Let x be the score by A students and Y the score of B.

A) $P(X>135) = \\P(Z>0.625)\\=0.0266$

B) Since X and Y are independent we have

X-Y is Normal with mean = 140-120 =20 and $Var (x-y)=Var(x)+Var(y) = 19$

$P(X-Y)>5\\\\=1-0.00029\\=0.9997$

C) For a group of 3, average has std deviation = $\frac{11}{\sqrt{3} } \\=6.351$

$P(\bar y >115)\\= P(z>\frac{-5}{6.351} \\=0.7856$

3 0

2 years ago

Which fraction is equivalent to fraction with numerator 6 and denominator negative 8? fraction with numerator negative 8 and den

Rzqust [24]

Numerator is the the number above the line on a fraction, while the denominator is the number underneath the line.

$\frac{6}{-8}$ is similar to $\frac{-6}{8}$

Fraction with numerator -6 and denominator 8

8 0

2 years ago

Read 2 more answers

3. Furnace repair bills are normally distributed with a mean of 269 dollars and a standard

Reil [10]

Hahahahshdujdkejdjdjdhduduudjdjd

3 0

2 years ago