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stealth61 [152]

2 years ago

9

the soccer team is planning to sell health bars for a fundraiser. the prices of purchasing health bars from two different compan

ies are represented by the system of equations shown, where x is the number of bars purchased and y is the total cost in dollars. company a: y = 0.75x company b: y = 10 0.50x how many bars would the team need to purchase from each company in order for the total cost to be equal?

2 answers:

zubka84 [21]2 years ago

4 0

40 bars __________________

k0ka [10]2 years ago

4 0

Answer:

The team needs to buy 40 health bars.

Step-by-step explanation:

We are given that,

Number of bars purchased = x

Total cost of the bars = y (in dollars)

The prices of purchasing health bars from different companies are given by,

Company A: $y = 0.75x$

Company B: $y = 10+0.50x$

Now, the teams needs to find the number of bars so that the cost are equal.

That is, we get,

$0.75x=10+0.50x\\0.25x=10\\x=40$

Hence, the team needs to buy 40 health bars.

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The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 22

NISA [10]

Answer:

a) $v(2\,s) = 2.9\,\frac{m}{s}$ , b) $v(4\,s) = -16.7\,\frac{m}{s}$ , c) $t = 2.296\,s$ , d) $h (2.296\,s) = 27.829\,m$ , e) $t \approx 4.679\,s$ , f) $v(4.679\,s) = -23.354\,\frac{m}{s}$

Step-by-step explanation:

The velocity function can be derived by the differentiating the height function:

$v = 22.5-9.8\cdot t$

Velocities after 2 and 4 seconds are, respectively:

a) $v(2\,s) = 2.9\,\frac{m}{s}$

b) $v(4\,s) = -16.7\,\frac{m}{s}$

The maximum height is reached when velocity is zero. Then:

$22.5-9.8\cdot t = 0$

c) $t = 2.296\,s$

The maximum height is:

d) $h (2.296\,s) = 27.829\,m$

The time required to hit the ground is:

$-4.9\cdot t^{2}+22.5\cdot t +2 = 0$

Roots of the second-order polynomial are:

$t_{1} \approx 4.679\,s$

$t_{2} \approx -0.087\,s$

Only the first root is physically reasonable.

e) $t \approx 4.679\,s$

The velocity when the projectile hits the ground is:

f) $v(4.679\,s) = -23.354\,\frac{m}{s}$

7 0

1 year ago

Out of 498 applicants for a job, 187 have over 10 years of experience and 127 have over 10 years of experience and have a gradua

Kitty [74]

Answer:

the probability that randomly selected applicants over 10 years of experience is 0.6791

Step-by-step explanation:

The computation of the probability that randomly selected applicants over 10 years of experience is as follows:

Total would be

= 187 have 10 + years experience

Now

P(graduate | 10+) = (graduate and 10+ years experience) ÷ (10 + years of experience)

= 127 ÷ 187

= 0.6791

Hence, the probability that randomly selected applicants over 10 years of experience is 0.6791

3 0

1 year ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

adoni [48]

Step-by-step explanation

<h3>Prerequisites:</h3>

<u>You need to know: </u>

$b^2 - 4ac = 0 \Rightarrow 1 solution$

$b^2 - 4ac > 0 \Rightarrow 2 solutions$

$b^2 - 4ac < 0 \Rightarrow No\ real\ solutions$

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$2x^2-7x-9 = 0$

$b^2 - 4ac$

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2 Solutions

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$b^2 - 4ac$

$-4^2 - 4(1)(4) = 0$

1 Solution

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$4x^2-3x-1 = 0$

$b^2 - 4ac$

$-3^2 - 4(4)(-1) = 25$

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$x^2-2x-8 = 0$

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2 Solutions

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$3x^2+5x+3 = 0$

$b^2 - 4ac$

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3 0

2 years ago

Read 2 more answers

Write the numbers in ascending order

nadezda [96]

-√2, 0, √5, 13/4

-1.5, 3/4, 3, √10

-3/2, -3/7, 0.75, 2

8 0

2 years ago

If y varies directly as x, and y is 400 when x is r and y is r when x is 4, what is the numeric constant of variation in this

otez555 [7]

Answer:

10

Step-by-step explanation:

If there is a direct relation between two variables x and y then it can be represented as

y = kx ,

where y is dependent variable

x is independent variable

k is constant of variation

_____________________________

First condition

y = 400

x = r

using y = kx then relationship will be

400 = kr

finding k here

k = 400/r

Second condition

y = r

x = 4

using y = kx then relationship will be

r = 4k

finding k

k = r/4

since in both condition equation is same

thus, value of k will also be same

thus,

400/r = r/4

=> 400*4 = r*r

=> 1600 = r^2

$\sqrt{r^{2} } = \sqrt{1600} \\r = 40$

Thus, 40 is the value of r

k = r/4 = 40/4 = 10

Thus, constant of variation is 10 which is correct choice.

To cross validate

k = 400/r = 400/40 = 10

7 0

1 year ago

Read 2 more answers