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Lemur [1.5K]
1 year ago
12

what is the first step when rewriting y = 3x2 9x – 18 in the form y = a(x – h)2 k? 3 must be factored from 3x2 9x x must be fact

ored from 3x2 9x 9 must be factored from 9x – 18 3 must be factored from 3x2 – 18
Mathematics
2 answers:
Bad White [126]1 year ago
8 0

Answer:

Option A - 3 must be factored from  3x^2+9x

Step-by-step explanation:

Given : Function y=3x^2+9x-18

To find : What is the first step when rewriting  y=3x^2+9x-18 in the form y = a(x -h)^2+k.

Solution :

To convert into the form  y = a(x -h)^2+k we follow the steps as:

Function y=3x^2+9x-18

Step 1- 3 must be factored from  3x^2+9x

y=3(x^2+3x)-18

Step 2 - Completing the square by adding and subtracting \frac{9}{4} (square the half of 9)

y=3(x^2+3x+\frac{9}{4}-\frac{9}{4})-18

Step 3- Solve

y=3(x+\frac{3}{2})^2-\frac{27}{4}-18

y=3(x+\frac{3}{2})^2-\frac{99}{4}

This is in the form y = a(x -h)^2+k

where, a= 3 , k=\frac{-99}{4} and  h=\frac{-3}{2}

Therefore, Option A is correct.

3 must be factored from  3x^2+9x

QveST [7]1 year ago
5 0
Steps in rewriting :
y = 3 x² + 9 x - 18 = 3 ( x² + 3 x ) - 18 = 3 (( x² + 3 x + 9/4 ) - 9/4) - 18 = 
= 3 ( x + 3/2 )² - 27/4 - 18 = 3 ( x + 3/2 )² - 99/4
Answer:
A ) 3 must be factored from 3 x² + 9 x.
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Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

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6 0
2 years ago
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In high-school 135 freshmen were interviewed.
timama [110]

Answer:

a) n(none) = 25

b) n(PE but not Bio) = 25

c) n(ENG but not both BIO and PE) = 55

d) n(students that did not take Eng or Bio) = 40

e) P( Students did not take exactly two subjects) = 0.65

Step-by-step explanation:

From the Venn diagram drawn:

a) Number of students that took none

n(Freshmen) = 135

n(all three) = 5

n (PE and Bio) = 10

n(PE and Eng) = 15

n(Bio and Eng) = 7

n (PE and Bio only) = 10 - 5 = 5

n(PE and Eng only) = 15 - 5 = 10

n(Bio and Eng only) = 7 - 5 = 2

n(PE only) = 35 - 5 - 5 - 10 = 15

n(Bio only) = 42 - 5 - 5 - 2 = 30

n(Eng only) = 60 - 10 - 5 -2 = 43

n(Freshmen) = n(PE only) + n(Bio only) + n(Eng only) + n(PE and Bio only) + n(PE and Eng only) + n(Bio and Eng only) + n(all three) + n(none)

135 = 15 + 30 + 43 + 5 + 10 + 2 + 5 + n(none)

135 = 110 + n(none)

n(none) = 135 - 110

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b)Number of students that too PE but not Bio

n(PE but not bio)= n(PE only) + n(PE and Eng only)

n(PE but not Bio) = 15 + 10

n(PE but not Bio) = 25

c) Number of students that took ENG but not both BIO and PE

n(ENG but not both BIO and PE) = n(Eng only) + n(Eng and Bio only) + n(Eng and PE only) = 43 + 2 + 10

n(ENG but not both BIO and PE) = 55

d) Number of students that did not take ENG or BIO

n( students that did not take Eng or Bio) = n(PE only) + n(none)

n(students that did not take Eng or Bio) = 15 + 25

n(students that did not take Eng or Bio) = 40

e) Probability that a randomly-chosen student from this group did not take exactly two subjects

n( Students that did not take exactly two subjects) = n(PE only) + n(Bio only) + n(Eng only)

n( Students that did not take exactly two subjects) = 15 + 30 + 43

n( Students that did not take exactly two subjects) = 88

P( Students did not take exactly two subjects) = 88/135

P( Students did not take exactly two subjects) = 0.65

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Next, we have to calculate the actual number sold by using the formula given below:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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The square root of c^2 is c.

The square root of 81 is 9.

c=9

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