Let x be a random variable representing the number of skateboards produced
a.) P(x ≤ 20,555) = P(z ≤ (20,555 - 20,500)/55) = P(z ≤ 1) = 0.84134 = 84.1%
b.) P(x ≥ 20,610) = P(z ≥ (20,610 - 20,500)/55) = P(z ≥ 2) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275 = 2.3%
c.) P(x ≤ 20,445) = P(z ≤ (20,445 - 20,500)/55) = P(z ≤ -1) = 1 - P(z ≤ 1) = 1 - 0.84134 = 0.15866 = 15.9%
Answer: THE GRAPH IS ATTACHED.
Step-by-step explanation:
We know that the lines are:
Solving for "y" from the first line, we get:
In order to graph them, we can find the x-intercepts and the y-intercepts.
For the line the x-intercepts is:
And the y-intercept is:
For the line 
the x-intercepts is:
And the y-intercept is:
Now we can graph both lines, as you can observe in the image attached (The symbols 
and 
indicates that the lines must be dashed).
By definition, the solution is the intersection region of all the solutions in the system of inequalities.
Answer:
Step-by-step explanation: I believe the answer would be (4, 0.1).
When plotting a residual, use the x-value, in this case 4, and the residual value as the y. (4, 0.1) The 4 is the x value, and the 0.1 replaces the y value. In the table the column headers will show you what the x, y, and residuals are. Just disregard the y-value and "predicted" and "given" columns, they are not needed when plotting the residual. I really hope this helps, and I hope I explained it well!
Answer:
The smallest bag that has enough food to feed his bag for one month
= 3.6 kilogram
Step-by-step explanation:
The quantity of dry food Ray feeds his dog = 0.12 kilogram
So the quantity of food he feeds his dog in one month
= 0.12 × 30 ∵ since 1 month = 30 days
= 3.6 kilogram
The smallest bag that has enough food to feed his bag for one month
= 3.6 kilogram
