Answer:
0.33411
The probability that a particular criminal trial lasted atleast 24 days is 0.33411
Step-by-step explanation:
The random variable X is normally distributed with a mean of 21 and standard deviation of 7
;
X ~ N(μ = 21 ; σ = 7)
X ~ N(21, 7)
Probability that a trial lasted atleast 24 days :
P(X ≥ 24) :
The standardized score :
Z = (x - μ) / σ ; (24 - 21) / 7 ; 3 / 7 = 0.4286
Hence,
P(Z ≥ 0.4286) = 0.33411
The probability that a particular criminal trial lasted atleast 24 days is 0.33411
Isolate the variable by dividing each side by factors that don't contain the variable.
x = 2
Answer:
Shift 2 unit left
Flip the graph about y-axis
Stretch horizontally by factor 2
Shift vertically up by 2 units
Step-by-step explanation:
Given:
Parent function: 
Transformation function: 
Take -2 common from transform function f(x)
![f(x)=\log[-2(x+2)]+2](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D%2B2)
Now we see the step-by-step translation

Shift 2 unit left ( x → x+2 )

Flip the graph about y-axis ( (x+2) → - (x+2) )
![f(x)=\log[-(x+2)]](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-%28x%2B2%29%5D)
Stretch horizontally by factor 2 [ -x(x+2) → -2(x+2) ]
![f(x)=\log[-2(x+2)]](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D)
Shift vertically up by 2 units [ f(x) → f(x) + 2 ]
![f(x)=\log[-2(x+2)]+2](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D%2B2)
Simplify the function:

Hence, Using four step of transformation to get new function 
Answer: There are 3 strips that can be cut from the roll of ribbon.
Step-by-step explanation:
since we have given that
Length of a ribbon is given by

Length of pieces of ribbon cut into strips is given by

So, we need to find the number of strips that can be cut is given by

Hence, there are 3 strips that can be cut from the roll of ribbon.
36/4 = 9 per hat
56/7 = 8 per hat
no, they are not equivalent