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2 years ago

10

The area of an oil spill is doubling in size every day. At the start of the day on May 1, the oil spill covers 20 square meters.

During which day will the area exceed 500 square meters?

1 answer:

ozzi2 years ago

5 0

Answer:

May 6

Step-by-step explanation:

20 x 2 = 40 40 x 2 = 80 80 x 2 = 160 x 2 = 320 320 x 2 = 640 after 5 days on may 6 it will surpass 500 meters.

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Each locker is shaped like a rectangular prism. Which has more storage space? explain/

seropon [69]

Locker 1 has more storage space because it has a greater volume.
The volume of locker 1 is 8,640 (48x15x12)
The volume of locker 2 is 7,200 (60x10x12)

I hope this helps.

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2 years ago

A child wanders slowly down a circular staircase from the top of a tower. With x,y,zx,y,z in feet and the origin at the base of

babymother [125]

Answer:

a) The tower is 90 feet tall

b) She reaches the bottom at t = 18 minutes.

c) Her speed at time t is 5 \sqrt[]{5} ft/minute

d) Her acceleration at time t is 10 ft/minute^2

Step-by-step explanation:

Consider the path described by the child as going down the tower to have the following parametrization $\gamma(t) = (10\cos t, 10 \sin t, 90-5t)$

a) Assuming that the child is at the top of the tower when she starts going down, we have that at the initial time (t=0) we will have the value of the height of the tower. That is z = 90-5*0 = 90 ft.

b) The child reaches the bottom as soon as z =0. We want to find the value of t that does that. Then we have 0 = 90-5t, which gives us t = 18 minutes.

c) Given the parametrization we are given, the velocity of the child at time t is given by $\frac{d\gamma}{dt}= (\frac{d}{dt}(10\cos t), \frac{d}{dt} (10 \sin t ), \frac{d}{dt}(90-5t)) = (-10 \sin t, 10 \cos t, -5)$ . The speed is defined as the norm of the velocity vector,

so, the speed at time t is given by $v = \sqrt[]{(-10 \sin t)^2+(10 \cos t)^2+(-5)^2} = \sqrt[]{100(\sin^2 t + \cos^2 t)+25} = \sqrt[]{125}= 5 \sqrt[]{5}$

d) ON the same fashion we want to know the norm of the second derivative of $\gamma$ .

We have that $\gamma ^{''}(t) =(-10\cost t, -10 \sin t , 0)$ so the acceleration is given by $\sqrt[]{100(\cos^2 t+ \sin^2 t )} = 10$

6 0

2 years ago

What do the differences between the points (as shown on the graph) represent?

Mekhanik [1.2K]

Answer:

They represent the rise and run of the graph.

Step-by-step explanation:

<em>The difference between the x-axis of the points represents the "run" of the graph (or how much you should run along x-axis to get to the next point.)</em>

<em>The difference between the y-axis of of the points represents the "rise" of the graph (or how much you should rise up the y-xis to get to the next point).</em>

The ratio of rise to run is the slope of the graph, which tells us how many steps should we take on the y-axis for every step we move forward on the x-axis.

8 0

2 years ago

Read 2 more answers

The area of a square is stored in a double variable named area. write an expression whose value is length of the diagonal of the

lbvjy [14]

First of all, a bit of theory: since the area of a square is given by

$A = s^2$

where s is the length of the square. So, if we invert this function we have

$s = \sqrt{A}$ .

Moreover, the diagonal of a square cuts the square in two isosceles right triangles, whose legs are the sides, so the diagonal is the hypothenuse and it can be found by

$d = \sqrt{s^2+s^2} = \sqrt{2s^2} = s\sqrt{2}$

So, the diagonal is the side length, multiplied by the square root of 2.

With that being said, your function could be something like this:

double diagonalFromArea(double area) {

double side = Math.sqrt(area);

double diagonal = side * Math.sqrt(2);

return diagonal;

}

3 0

2 years ago

Here is a scale drawing of a window frame that uses a scale of 1 cm to 6 inches.Create another scale drawing of the window frame

Tresset [83]

Answer:

Step-by-step explanation:

Below is the rectangle in the attachment.

Current scale:

1 cm : 6 inches

If the dimensions of the rectangle is:

Length = a cm

Width = b cm

Using the scale:

Length = a × 6 inches

Width = b × 6 inches

Using the same dimensions of the rectangle is:

Length = a cm

Width = b cm

Using the scale:

Length = a × 12 inches

Width = b × 12 inches

Note that there is an enlargement of the rectangle to form the new rectangle. The length and width of new rectangle drawn will be 2 × the length and width of the rectangle seen below.

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2 years ago