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Helga [31]
1 year ago
14

Casey is deciding which of two landscapers to hire. Each landscaper charges an hourly rate plus a fee for each job. Casey correc

tly wrote and solved a system of linear equations by substitution. In his work, he substituted an expression for one variable and solved for the other. This resulted in the equation 5 = 20. What can Casey conclude? One landscaper charges $20 for 5 hours of work. One landscaper’s hourly rate is $15 lower than the other landscaper’s. Both landscapers charge the same hourly rate and the same fee per job. Both landscapers charge the same hourly rate, but not the same fee per job.
Mathematics
2 answers:
kenny6666 [7]1 year ago
9 0

Answer:

Both charge the same hourly rate, but a different fee.

Step-by-step explanation:

me 100

ZanzabumX [31]1 year ago
7 0

which of the two landscapes to hire each landscapes charger an hour rate plus a fee for each job the result of the equator into 20 $20 for 5 hours both landscape charge the same hour rate but not the same fee per job give me your answer

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A weatherman collected data on snow accumulation. A line of best fit was computed. The equation for the line is: y = 1.5x + 0.12
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Answer:

5x-12=42 over 3 subtract that and you will get 1

Step-by-step explanation:

8 0
1 year ago
Annie is creating a stencil for her artwork using a coordinate plane. The beginning of the left edge of the stencil falls at (2,
taurus [48]

Answer:

(A)(12, 9)

Step-by-step explanation:

Given:

The beginning of the left edge of the stencil falls at (2, −1).

A point, say Q on the stencil is at  (4, 1).

Point Q divides the stencil into the ratio 1:4.

We are required to find the end of the stencil.

Mathematically, Point Q divides the stencil internally in the ratio 1:4.

For internal division of a line with beginning point (x_1,y_1) and end point (x_2,y_2) in the ratio m:n, we use the formula

Q(x,y)=(\dfrac{mx_2+nx_1}{m+n} ,\dfrac{my_2+ny_1}{m+n} )

(x_1,y_1)=(2, -1), (x_2,y_2)=?, Q(x,y)=(4,1), m:n=1:4

Therefore:

(4,1)=(\dfrac{1x_2+4*2}{1+4} ,\dfrac{1y_2+4*-1}{1+4} )\\(4,1)=(\dfrac{x_2+8}{5} ,\dfrac{y_2-4}{5} )\\$Therefore:\\\dfrac{x_2+8}{5}=4\\x_2+8=4X5\\x_2=20-8=12\\$Similarly\\\dfrac{y_2-4}{5}=1\\y_2-4=5\\y_2=4+5=9\\(x_2,y_2)=(12,9)

The correct option is A.

6 0
1 year ago
Read 2 more answers
The front walkway from the street to Pam's house has an area of 250ft^2. Its length is two less than four times its width. Find
OleMash [197]

Answer: the length of the walkway is 30.64ft

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Step-by-step explanation:

Since the walkway has length and width, it is rectangular in shape. For a rectangle, the two lengths and two widths are equal. The area is expressed as length, L × Width,W.

The front walkway from the street to Pam's house has an area of 250ft^2. It means that

LW = 250

Its length is two less than four times its width. It means

L = 4W - 2

Substituting L = 4W - 2 into LW = 250, it becomes

W(4W - 2) = 250

4W^2 - 2W- 250 = 0

Using the general formula for quadratic equations,

W = [- b ± √b^2 - 4ac]/2a

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b = -2

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W= [- - 2 ±√-2^2 -4(4 × -250)]/2×4

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= (2 ±63.277)/8

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W = 8.16 or W = - 7.91

Since the width cannot be negative, width = 8.16 ft

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8 0
2 years ago
Read 2 more answers
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morpeh [17]

Answer:

a: 28 < µ < 34

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We can now construct our confidence interval.  See the second attached photo for the construction steps.

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The t-value is: 1.943

We rounded down to the nearest person in the interval because we don't want to over estimate.  It said 28.55, so more than 28 but not quite 29, so if we use 29 as the lower limit, we could over estimate.  It's better to use 28 and underestimate a little when considering customer flow.

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