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quester [9]
2 years ago
8

A very small dinosaur, the Microraptor, was only 1.3 feet long, One of the larger dinosaurs, the diplodocus, was about 91 feet l

ong. How many times as long as the microraptor was the diplodocus?
Mathematics
2 answers:
snow_lady [41]2 years ago
6 0
Divide 90 by 1.3 and you will get your answer.

Do it yourself!  just follow instructions!

<3
sukhopar [10]2 years ago
4 0
70 ft but i'm probably wrong
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Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the so
Georgia [21]
In order to construct this equation, we will use the variables:
V to represent mixture volume (40 ml)
C to represent mixture concentration (0.32)
v₁ to represent volume of first solution (40 / 4 = 10 ml)
c₁ to represent concentration of first solution (0.2)
v₂ to represent the volume of the second solution (40 * 3/4 = 30 ml)
c₂ to represent the concentration of the second solution 


We know that the total amount of substance, product of the volume and concentration, in the final solution is equal to the individual amounts in the two given solutions. Thus:
VC = v₁c₁ +  v₂c₂
40(0.32) = 10(0.2) + 30c
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What is the greatest possible percent error in calculating the volume of a box measured to the nearest inch with sides of 5 in.,
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Rebecca has 30 small glass tiles in the shape of parallelograms as shown in the diagram. She plans to use them to create a small
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The following histogram presents the amounts of silver (in parts per million) found in a sample of rocks. One rectangle from the
gladu [14]

Answer:

  • <u><em>The height of the missing rectangle is 0.15</em></u>

Explanation:

The image attached has the mentioned <em>histogram</em>.

Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.

Only the rectangle for the class [3,4] is missing.

The height of each rectangle is the relative frequency of the corresponding class.

The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.

In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.

<u>1. Sum of the known relative frequencies</u>:

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<u>2. Missing frequency</u>:

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<u>3. Conclusion</u>:

  • The height of the missing rectangle is 0.15

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